
Concept explainers
Solar Eclipse on Neptune (Refer to Exercise 69.) The sun’s distance from Neptune is approximately 2,800,000,000 mi (2.8 billion mi). The largest moon of Neptune is Triton, with a diameter of approximately 1680 mi. (Source: World Almanac and Book of Facts.)
Calculate the maximum distance, to the nearest thousand miles, that Triton can be from Neptune for a total eclipse of the sun to occur on Neptune. (Hint: Use similar
Triton is approximately 220,000 mi from Neptune. Is it possible for Triton to cause a total eclipse on Neptune?
Solar Eclipse on Earth The sun has a diameter of about 865,000 mi with a maximum distance from Earth's surface of about 94,500,000 mi. The moon has a smaller diameter of 2159 mi. For a total solar eclipse to occur, the moon must pass between Earth and the sun. The moon must also be close enough to Earth for the moon's umbra (shadow) to reach the surface of Earth. (Source: Karttunen, H., P. Kröger, H. Oja, M. Putannen, and K. Donners, Editors, Fundamental Astronomy, Fourth Edition, Springer-Verlag.)
Calculate the maximum distance, to the nearest thousand miles, that the moon can be from Earth and still have a total solar eclipse occur. (Hint: Use similar triangles.)
The closest approach of the moon to Earth's surface was 225,745 mi and the farthest was 251,978 mi. (Source: World Almanac and Book of Facts.) Can a total solar eclipse occur every time the moon is between Earth and the sun?

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Chapter 1 Solutions
Trigonometry, Books a la Carte Edition plus MyLab Math with Pearson eText -- Access Card Package (11th Edition)
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- 2) A radio transmission tower is 130 feet tall. How long should a guy wire be if it is to be attached 6 feet from the top and is to make an angle of 20° with the ground? Give your answer to the nearest tenth of a foot.arrow_forward4) Two sides and an angle are given. Determine whether the given information results in one triangle, two triangles, or no triangle at all. Solve any triangle(s) that results. b=6, c=7, B = 80° A) one triangle B=40°, A = 60°, a = 13 C) one triangle C 39°, A 61°, a = 15 = B) one triangle C=41°, A = 59°, a = 17 D) no trianglearrow_forward7) A painter needs to cover a triangular region 63 meters by 67 meters by 74 meters. A can of paint covers 70 square meters. How many cans will be needed?arrow_forward
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