
(a)
Interpretation:
The relationship between Q and K at 1, 3 and 4 point in the graph needs to be determined.
Concept introduction:
A system is said to be in equilibrium, if there is no change in the concentration and pressure of the system takes place with time.
The reaction is in forward direction if the value of equilibrium constant is greater than the reaction quotient Q.It is in equilibrium if K is equal to Q and in reverse direction if K is less than Q.
(b)
Interpretation:
The disturbance at point 2 needs to be explained.
Concept introduction:
A system is said to be in equilibrium, if there is no change in the concentration and pressure of the system takes place with time.
The reaction is in forward direction if the value of equilibrium constant is greater than the reaction quotient Q. It is in equilibrium if K is equal to Q and in reverse direction if K is less than Q.
(c)
Interpretation:
A graph needs to be drawn if partial pressure of A is increased.
Concept introduction:
A system is said to be in equilibrium, if there is no change in the concentration and pressure of the system takes place with time.
The reaction is in forward direction if the value of equilibrium constant is greater than the reaction quotient Q. It is in equilibrium if K is equal to Q and in reverse direction if K is less than Q.

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Chapter 12 Solutions
Bundle: Chemistry: Principles and Reactions, 8th, Loose-Leaf + OWLv2, 1 term (6 months) Printed Access Card
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- Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction. For the decomposition reaction of N2O5(g): 2 N2O5(g) · 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 -> NO2 + NO3_(K1) NO2 + NO3 →> N2O5 (k-1) → NO2 + NO3 → NO2 + O2 + NO (K2) NO + N2O5 → NO2 + NO2 + NO2 (K3) Give the expression for the acceptable rate. (A). d[N₂O] dt = -1 2k,k₂[N205] k₁+k₂ d[N₂O5] (B). dt =-k₁[N₂O₂] + k₁[NO2][NO3] - k₂[NO2]³ (C). d[N₂O] dt =-k₁[N₂O] + k₁[N205] - K3 [NO] [N205] (D). d[N2O5] =-k₁[NO] - K3[NO] [N₂05] dtarrow_forwardA 0.10 M solution of acetic acid (CH3COOH, Ka = 1.8 x 10^-5) is titrated with a 0.0250 M solution of magnesium hydroxide (Mg(OH)2). If 10.0 mL of the acid solution is titrated with 20.0 mL of the base solution, what is the pH of the resulting solution?arrow_forwardFor the decomposition reaction of N2O5(g): 2 N2O5(g) → 4 NO2(g) + O2(g), the following mechanism has been proposed: N2O5 NO2 + NO3 (K1) | NO2 + NO3 → N2O5 (k-1) | NO2 + NO3 NO2 + O2 + NO (k2) | NO + N2O51 NO2 + NO2 + NO2 (K3) → Give the expression for the acceptable rate. → → (A). d[N205] dt == 2k,k₂[N₂O₂] k₁+k₁₂ (B). d[N2O5] =-k₁[N₂O] + k₁[NO₂] [NO3] - k₂[NO₂]³ dt (C). d[N2O5] =-k₁[N₂O] + k [NO] - k₂[NO] [NO] d[N2O5] (D). = dt = -k₁[N2O5] - k¸[NO][N₂05] dt Do not apply the calculations, based on the approximation of the stationary state, to make them perform correctly. Basta discard the 3 responses that you encounter that are obviously erroneous if you apply the formula to determine the speed of a reaction.arrow_forward
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