Explanation Given Information: The provided line passing through point ( − 1 , − 1 ) has slope − 1 4 and the first coordinates are ( 0 , ) ; ( 1 , ) ; ( − 2 , ) . Formula Used: The equation of the line the formula is y − y 1 = m ( x − x 1 ) . Calculation: Consider that the line passing through point ( − 1 , − 1 ) has slope − 1 4 and the first coordinates are ( 0 , ) ; ( 1 , ) ; ( − 2 , ) . Calculate the equation of the line using the formula y − y 1 = m ( x − x 1 ) as follows: The line passing through the point ( − 1 , − 1 ) has slope − 1 4 . So, m = − 1 4 , x 1 = − 1 and x 2 = − 1 and put the values of m = − 1 4 , x 1 = − 1 and x 2 = − 1 in the equation y − y 1 = m ( x − x 1 ) , y − y 1 = m ( x − x 1 ) y − ( − 1 ) = − 1 4 ( x − ( − 1 ) ) y + 1 = − 1 4 ( x + 1 ) y + 1 = − 1 4 x − 1 4 Subtract 1 from both the sides of the equation y + 1 = − 1 4 x − 1 4 , y + 1 − 1 = − 1 4 x − 1 4 − 1 y = − 1 4 x − 5 4 Now, put the first coordinates in the equation y = − 1 4 x − 5 4 to determine the second coordinate

MyLab Math plus Pearson eText -- Standalone Access Card -- for Finite Mathematics & Its Applications (12th Edition)

12th Edition

ISBN: 9780134765723

Author: Larry J. Goldstein, David I. Schneider, Martha J. Siegel, Steven Hair

Publisher: PEARSON

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Chapter 1.2, Problem 61E

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To calculate: The second coordinate for their first coordinates are (0, );(1, );(−2, ) of the line passing through the point (−1,−1) and having slope −14.

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Chapter 1.2, Problem 60E

Chapter 1.2, Problem 62E

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MyLab Math plus Pearson eText -- Standalone Access Card -- for Finite Mathematics & Its Applications (12th Edition)

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The second coordinate for their first coordinates are ( 0 , ) ; ( 1 , ) ; ( − 2 , ) of the line passing through the point ( − 1 , − 1 ) and having slope − 1 4 .

Solution Summary: The author explains how to calculate the equation of the line using the formula y-y_1=m(x-

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To calculate: The second coordinate for their first coordinates are (0, );(1, );(−2, ) of the line passing through the point (−1,−1) and having slope −14.

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Chapter 1 Solutions