Explanation Given info: α , β are Roots of a x 2 + b x + c where b = − α − β and c= α β Concept used: If α , β are roots of quadratic then quadratic is given a ( x − α ) ( x − β ) Where a is constant but not equal to zero. Calculation: If α , β are roots of quadratic then quadratic is given by a ( x − α ) ( x − β ) a ( x − α ) ( x − β ) = a [ x ( x − β ) − α ( x − β ) ] = a [

3rd Edition

ISBN: 9781464125263

Author: Jon Rogawski, Colin Adams

Publisher: W.H. Freeman & Co

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Chapter 1.2, Problem 61E

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Prove viete’s formula: the quadratic polynomial with α and β as roots is x2+bx+c where b=−α−β and c=αβ

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Chapter 1.2, Problem 60E

Chapter 1.3, Problem 1PQ

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Chapter 1 Solutions

Calculus - Standalone book

Ch. 1.1 - Prob. 1PQ Ch. 1.1 - Prob. 2PQ Ch. 1.1 - Prob. 3PQ Ch. 1.1 - Prob. 4PQ Ch. 1.1 - Prob. 5PQ Ch. 1.1 - Prob. 6PQ Ch. 1.1 - Prob. 7PQ Ch. 1.1 - Prob. 8PQ Ch. 1.1 - Prob. 9PQ Ch. 1.1 - Prob. 10PQ

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Prove viete’s formula: the quadratic polynomial with α and β as roots is x 2 + b x + c where b = − α − β and c = α β

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Prove viete’s formula: the quadratic polynomial with α and β as roots is x2+bx+c where b=−α−β and c=αβ

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Chapter 1 Solutions