(a) Interpretation: The products formed by the reaction of squalene with O 3 followed by Zn , H 2 O are to be drawn. Concept introduction: In the presence of ozone and Zn , H 2 O , oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn , H 2 O .

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Answer 1

Question

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

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Can the target compound at right be efficiently synthesized in good yield from the unsubstituted benzene at left? ? starting material target If so, draw a synthesis below. If no synthesis using reagents ALEKS recognizes is possible, check the box under the drawing area. Be sure you follow the standard ALEKS rules for submitting syntheses. + More... Note for advanced students: you may assume that you are using a large excess of benzene as your starting material. C :0 T Add/Remove step G

The following equations represent the formation of compound MX. What is the AH for the electron affinity of X (g)? X₂ (g) → 2X (g) M (s) → M (g) M (g) M (g) + e- AH = 60 kJ/mol AH = 22 kJ/mol X (g) + e-X (g) M* (g) +X (g) → MX (s) AH = 118 kJ/mol AH = ? AH = -190 kJ/mol AH = -100 kJ/mol a) -80 kJ b) -30 kJ c) -20 kJ d) 20 kJ e) 156 kJ

A covalent bond is the result of the a) b) c) d) e) overlap of two half-filled s orbitals overlap of a half-filled s orbital and a half-filled p orbital overlap of two half-filled p orbitals along their axes parallel overlap of two half-filled parallel p orbitals all of the above

Answer 2

Question

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

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Answer 3

Question

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

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Answer 4

Question

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

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Answer 5

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 6

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 7

Chapter 12, Problem 48P

Interpretation Introduction

(a)

Interpretation: The products formed by the reaction of squalene with O3 followed by Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 8

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 9

Interpretation Introduction

(b)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In the presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage, both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 10

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 11

Interpretation Introduction

(c)

Interpretation: The products formed when the given compounds are treated with ozone and Zn,H2O are to be drawn.

Concept introduction: In presence of ozone and Zn,H2O, oxidative cleavage occurs. In oxidative cleavage both the sigma and pi bond of the alkene is broken and two carbonyl compounds are formed. When ozone is added to the alkene, unstable intermediate molozonide is formed which rearranges to ozonide. This ozonide is reduced to form two carbonyl compounds in presence of Zn,H2O.

Answer 12

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Answer 13

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Answer 14

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Answer 15

Ch. 12.1 - Prob. 1P Ch. 12.3 - Problem 12.2 What alkane is formed when each...Ch. 12.3 - Prob. 3P Ch. 12.3 - Prob. 4P Ch. 12.3 - Prob. 5P Ch. 12.3 - Prob. 6P Ch. 12.3 - Compound Molecular formula before...Ch. 12.4 - Problem 12.8 Draw the products formed when...Ch. 12.5 - Prob. 9P Ch. 12.5 - Prob. 10P

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