EBK UNDERSTANDING OUR UNIVERSE (THIRD E
EBK UNDERSTANDING OUR UNIVERSE (THIRD E
3rd Edition
ISBN: 9780393631760
Author: Blumenthal
Publisher: VST
bartleby

Concept explainers

Question
Book Icon
Chapter 12, Problem 38QAP

(a)

To determine

The lifetime of a star; compare it with given values in Table 12.1.

(a)

Expert Solution
Check Mark

Answer to Problem 38QAP

The lifetime of star is 56.6billion years; it is nearly equal to the given value.

Explanation of Solution

Write the expression for lifetime of a main sequence star.

Lifetime=(1×1010)(MSunMMS)2.5

Here, MSun is mass of the Sun and MMS is mass of the main-sequence star.

The above expression shows that the lifetime of star is inversely proportional to the mass of main-sequence star. Greater the mass of star compared to the Sun is; less would be its lifetime.

Conclusion:

Substitute 0.50MSun for MMS in equation (I).

Lifetime=(1×1010)(MSun0.50MSun)2.5=5.66×1010years(1billion years109years)=56.6billion years

Thus, the lifetime of star is 56.6billion years; it is nearly equal to the given value.

(b)

To determine

The lifetime of a star; compare it with given values in Table 12.1.

(b)

Expert Solution
Check Mark

Answer to Problem 38QAP

The lifetime of star is 0.11billion years; it is nearly equal to the given value.

Explanation of Solution

Write the expression for lifetime of a main sequence star.

Lifetime=(1×1010)(MSunMMS)2.5

Here, MSun is mass of the Sun and MMS is mass of the main-sequence star.

The above expression shows that the lifetime of star is inversely proportional to the mass of main-sequence star. Greater the mass of star compared to the Sun is; less would be its lifetime.

Conclusion:

Substitute 6.0MSun for MMS in equation (I).

Lifetime=(1×1010)(MSun6.0MSun)2.5=0.011×1010years(1billion years109years)=0.11billion years

Thus, the lifetime of star is 0.11billion years; it is nearly equal to the given value.

(c)

To determine

The lifetime of a star; compare it with given values in Table 12.1.

(c)

Expert Solution
Check Mark

Answer to Problem 38QAP

The lifetime of star is 56.6billion years; it is nearly equal to the given value.

Explanation of Solution

Write the expression for lifetime of a main sequence star.

Lifetime=(1×1010)(MSunMMS)2.5

Here, MSun is mass of the Sun and MMS is mass of the main-sequence star.

The above expression shows that the lifetime of star is inversely proportional to the mass of main-sequence star. Greater the mass of star compared to the Sun is; less would be its lifetime.

Conclusion:

Substitute 0.50MSun for MMS in equation (I).

Lifetime=(1×1010)(MSun0.50MSun)2.5=3.6×105×1010years(1million years106years)=0.36million years

Thus, the lifetime of star is 0.36million years; it is nearly equal to the given value.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
••63 SSM www In the circuit of Fig. 27-65, 8 = 1.2 kV, C = 6.5 µF, R₁ S R₂ R3 800 C H R₁ = R₂ = R3 = 0.73 MQ. With C completely uncharged, switch S is suddenly closed (at t = 0). At t = 0, what are (a) current i̟ in resistor 1, (b) current 2 in resistor 2, and (c) current i3 in resistor 3? At t = ∞o (that is, after many time constants), what are (d) i₁, (e) i₂, and (f) iz? What is the potential difference V2 across resistor 2 at (g) t = 0 and (h) t = ∞o? (i) Sketch V2 versus t between these two extreme times. Figure 27-65 Problem 63.
Thor flies by spinning his hammer really fast from a leather strap at the end of the handle, letting go, then grabbing it and having it pull him. If Thor wants to reach escape velocity (velocity needed to leave Earth’s atmosphere), he will need the linear velocity of the center of mass of the hammer to be 11,200 m/s. Thor's escape velocity is 33532.9 rad/s, the angular velocity is 8055.5 rad/s^2. While the hammer is spinning at its maximum speed what impossibly large tension does the leather strap, which the hammer is spinning by, exert when the hammer is at its lowest point? the hammer has a total mass of 20.0kg.
If the room’s radius is 16.2 m, at what minimum linear speed does Quicksilver need to run to stay on the walls without sliding down?  Assume the coefficient of friction between Quicksilver and the wall is 0.236.
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning
Text book image
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax
Text book image
Foundations of Astronomy (MindTap Course List)
Physics
ISBN:9781337399920
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning
Text book image
The Solar System
Physics
ISBN:9781337672252
Author:The Solar System
Publisher:Cengage
Text book image
Stars and Galaxies
Physics
ISBN:9781305120785
Author:Michael A. Seeds, Dana Backman
Publisher:Cengage Learning