Explanation Given information: At time t = 0 , the two helicopters H 1 and H 2 having a following straight-line paths. H 1 : x = 6 + 40 t , y = − 3 + 10 t , z = − 3 + 2 t (1) H 2 : x = 6 + 110 t , y = − 3 + 4 t , z = − 3 + t (2) The helicopter H 2 stops its flight at ( 446 , 13 , 1 ) and in a negligible amount of time it lands at ( 446 , 13 , 0 ) . Calculation: The helicopter H 2 stops its flight at ( 446 , 13 , 1 ) . Therefore, from equation (2) and point at ( 446 , 13 , 1 ) . 6 + 110 t = 446 110 t = 446 − 6 110 t = 440 t = 440 110 t = 4 hours From the given data, after 6 hours (4 hours + 2 hours) the helicopter H 1 heads towards is calculated by using equation (1) as follows: Substitute 6 for t in equation (1) to find the new point of the helicopter H 1

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ISBN: 9781323835029

Author: WEIR

Publisher: PEARSON C

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Chapter 12, Problem 2AAE

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Calculate the time t required to take helicopter $H1$ to reach helicopter $H2$ .

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Calculate the time t required to take helicopter H1<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>1</m:mn></m:msub></m:mrow></m:math> to reach helicopter H2<m:math><m:mrow><m:msub><m:mi>H</m:mi><m:mn>2</m:mn></m:msub></m:mrow></m:math>.

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Calculate the time t required to take helicopter $H1$ to reach helicopter $H2$ .