Explanation Given information: The provided equation is; 15 x − 15 x + 2 = 2 Formula used: Cancellation of the fractions by multiplication of least common multiple, A B + C D = E D The least common multiple of B , D and D is B D . Thus, multiply B D on both sides of the equation A B + C D = E D . ( A B + C D ) ⋅ B D = ( E D ) ⋅ B D Solution of a quadratic equation a x 2 + b x + c = 0 is; x = − b ± b 2 − 4 a c 2 a Calculation: Consider the equation as below, 15 x − 15 x + 2 = 2 The least common multiple of the denominators x , x + 2 and 1 is x ( x + 2 ) . Multiply the least common multiple x ( x + 2 ) on both sides of the equation 15 x − 15 x + 2 = 2 . Thus, ( 15 x − 15 x + 2 ) x ( x + 2 ) = ( 2 ) x ( x + 2 ) ( 15 x ) x ( x + 2 ) − ( 15 x + 2 ) x ( x + 2 ) = 2 ( x ) ( x + 2 ) Cancel the terms equal to 1. Thus, ( 15 x ) x ( x + 2 ) − ( 15 x + 2 ) x ( x + 2 ) = 2 ( x ) ( x + 2 ) 15 ( x + 2 ) − 15 x = 2 x 2 + 4 x 15 x + 30 − 15 x = 2 x 2 + 4 x 2 x 2 + 4 x − 30 = 0 Determine the factors of the equation 2 x 2 + 4 x − 30 = 0

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Author: BITTINGER

Publisher: Pearson Custom Publishing

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Chapter 12, Problem 29RE

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Chapter 12 Solutions

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Ch. 12.1 - Objective 11.3a: Factor trinomials of the type...Ch. 12.1 - Prob. 2SR Ch. 12.1 - Prob. 1DE Ch. 12.1 - Prob. 2DE Ch. 12.1 - Prob. 3DE Ch. 12.1 - Prob. 4DE Ch. 12.1 - Prob. 5DE Ch. 12.1 - Prob. 6DE Ch. 12.1 - Prob. 7DE Ch. 12.1 - Prob. 8DE

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The solution of the equation 15 x − 15 x + 2 = 2 .

Solution Summary: The author explains the formula used to calculate the solution of the equation 15x — the least common multiple of denominators B,Dand

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To calculate: The solution of the equation 15x−15x+2=2.

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Chapter 12 Solutions