
Explanation of Solution
Method definition:
//All the sub-lists of the given list of Strings gets printed.
/*elements!= null and elements contains no duplicates are the pre-condition*/
//method definition
public static void subsets(List<String> elements)
{
//define the list
List<String> chosen = new ArrayList<String>();
//call the method explore
explore(elements, chosen);
}
/*Helper recursive function defined to explore all the sub list from the given list of elements, choice is made assuming the given list of string is already chosen*/
//method definition
private static void explore(List<String> elements, List<String> chosen)
{
// base case; nothing left to choose
//validate whether the elements are empty
if (elements.isEmpty())
{
//display the chosen
System.out.println(chosen);
}
else
{
//define the choice that is for first element
String first = elements.remove(0);
// two explorations: one with this first element, one without
//add the first element
chosen.add(first);
//call the explore method
explore(elements, chosen);
//remove the element
chosen.remove(chosen.size() - 1);
//call the method
explore(elements, chosen);
// backtrack! 1st element is put back
elements...

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Chapter 12 Solutions
EBK BUILDING JAVA PROGRAMS
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