BIOLOGY 12E CONNECT ACCESS CARD
12th Edition
ISBN: 9781264938513
Author: Raven
Publisher: MCG
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Textbook Question
Chapter 12, Problem 1S
z1. Create a Punnett square for the following crosses and use this to predict
a. A monohybrid cross between individuals with the genotype Aa and Aa
b. A dihybrid cross between two individuals with the genotype AaBb
c. A dihybrid cross between individuals with the genotype AaBb and aabb
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. An allele A that is not lethal when homozygous causes rats to have yellow coats. The allele R of a separate gene that assorts independently produces a black coat. Together, A and R produce a grayish coat, whereas a and r produce a white coat. A gray male is crossed with a yel-low female, and the F1 is 3 8 yellow, 3 8 gray, 1 8 black, and 1 8 white. Determine the genotypes of the parents.
A. Theoretical: The Punnett square will be used to examine the theoretical outcome of possible monohybrid
crosses.
1. The first cross is between a Homozygous dominant parent (PP), and a Homozygous recessive or just simply
say recessive parent (pp):
a. Fill in the Punnett square. Each box represents a genotype possibility for an offspring.
b. Place the allele donated by each parent in the corresponding box. Now list the possible genotypes and
their corresponding phenotype.
c. If an individual's genotype is heterozygous, the dominant trait will be expressed in the phenotype.
Give the percent possible for the phenotypes.
P
Genotype:
p
Phenotype:
Phenotype % probable:
1| Page
2. Cross between a Homozygous dominant parent (PP) and a Heterozygous parent (Pp). Fill in as in step one.
3. Cross between a Heterozygous parent (Pp), and another Heterozygous parent (Pp). Fill-in as before.
4. Test cross: A test cross is between a recessive parent (pp), and a Heterozygous parent (Pp). Again, fill-in…
What could be the genotypic and phenotypic ratios for a typical mendelian trait showed in the picture?
Chapter 12 Solutions
BIOLOGY 12E CONNECT ACCESS CARD
Ch. 12.1 - Prob. 1LOCh. 12.1 - Explain the advantages of Mendels experimental...Ch. 12.2 - Evaluate the outcome of a monohybrid cross.Ch. 12.2 - Explain Mendels Principle of Segregation.Ch. 12.2 - Compare the segregation of alleles with the...Ch. 12.3 - Evaluate the outcome of a dihybrid cross.Ch. 12.3 - Explain Mendels Principle of Independent...Ch. 12.3 - Compare the segregation of alleles for different...Ch. 12.4 - Prob. 1LOCh. 12.4 - Prob. 2LO
Ch. 12.5 - Interpret data from testcrosses to infer unknown...Ch. 12.6 - Describe how assumptions in Mendels model result...Ch. 12.6 - Prob. 2LOCh. 12.6 - Explain the genetic basis for observed alterations...Ch. 12 - Inquiry question What confounding problems could...Ch. 12 - Prob. 2IQCh. 12 - Prob. 1DACh. 12 - Prob. 2DACh. 12 - Prob. 3DACh. 12 - What property distinguished Mendels investigation...Ch. 12 - The F1 generation of the monohybrid cross purple...Ch. 12 - The F1 plants from the previous question are...Ch. 12 - In a cross of Aa Bb cc X Aa Bb Cc, what is the...Ch. 12 - An organisms __________ is/are determined by its...Ch. 12 - Phenotypes like height in humans, which show a...Ch. 12 - Japanese four oclocks that are red and tall are...Ch. 12 - If the two genes in the previous question showed...Ch. 12 - What is the probability of obtaining an individual...Ch. 12 - Prob. 4ACh. 12 - Prob. 5ACh. 12 - Mendels model assumes that each trait is...Ch. 12 - z1. Create a Punnett square for the following...Ch. 12 - Explain how the events of meiosis can explain both...Ch. 12 - Prob. 3SCh. 12 - In mammals, a variety of genes affect coat color....
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- A. Part 1: F1 Generation Yellow Sampaguita- Homozygous recessive (cc) White Sampaguita- Homozygous dominant (CC) a. With the given sampaguita flowers, you will be crossing these two samples and identify the offspring using a punnet square. Indicate the ratio between each offspring B. Part 2: F2 generation a. With the results you have from Part 1 and using a punnet square, what are the offspring of your heterozygous parents to identify the F2 generation. Indicate the ratio between each offspring. Note: Please provide the punnet square and a detailed explanationarrow_forwardPurple flowers are dominant to white flowers. Identify the phenotypefor the following genotype Ff, FF, ff and determine if the genotype is heterozygous or homozygous. * For each row, you should select two columns. Purple flowers White flowers Heterozygous Homozygous Ff FF ff Brown eyes are dominant to blue eyes. Identify the phenotype for the following genotype BB, Bb, bb and determine if the genotype is heterozygous or homozygous. * 口 ロ口arrow_forwarda. 1 dominant allele will contribute 120/10 = 12 cm to the base height of the plant.b. The height of the parent plant 1 Genotype of the parent plant 1 – D1D1D2D2D3D3d4d4d5d5 The height of the parent plant 2 Genotype of the parent plant 2 – d1d1d2d2d3d3D4D4D5D5Contributing alleles – D4D4D5D5. The height of the plant without any contributing alleles would be 80 cm. The plant with genotype d1d1d2d2d3d3D4D4D5D5 has 4 contributing allele each of which contributes 12 cm to the base. Hence, the height of the plant with genotype d1d1d2d2d3d3D4D4D5D5 would be 80 + 12 + 12 + 12 + 12 = 128 cm. c. Parents – D1D1D2D2D3D3d4d4d5d5 × d1d1d2d2d3d3D4D4D5D5 Gametes – D1D2D3d4d5 × d1d2d3D4D5 F1 generation – D1d1D2d2D3d3D4d4D5d5 The height of the plants of F1 generation = 80 + 12 + 12 + 12 + 12 + 12 = 140 cm Hence, Genotype of the F1 = D1d1D2d2D3d3D4d4D5d5 Phenotype of…arrow_forward
- The colors of chicken feathers follow a codominant pattern. Both Black (B) and White (W) feathers are dominant phenotypes while checkered (BW) is the heterozygous phenotype. Show a cross between 2 checkered chickens. 1. P1: 2. Punnett Square: 3. Genotype symbols: 4. Genotype in words: 5. Genotypic ratio: 6. Genotypic %: 7. Phenotype symbols: 8. Phenotype in words: 9. Phenotypic ratio: 10. Phenotypic %:arrow_forward. The genotype r/r ; p/p gives fowl a single comb, R/− ; P/−gives a walnut comb, r/r ; P/− gives a pea comb, andR/− ; p/p gives a rose comb (see the illustrations).Assume independent assortment.Single Walnut Pea Rosea. What comb types will appear in the F1 and in the F2and in what proportions if single-combed birds arecrossed with birds of a true-breeding walnut strain?b. What are the genotypes of the parents in a walnut ×rose mating from which the progeny are 38 rose, 38 walnut,18 pea, and 18 single?c. What are the genotypes of the parents in a walnut ×rose mating from which all the progeny are walnut?d. How many genotypes produce a walnut phenotype?Write them outarrow_forward4) The round pea seed allele (R) is dominant, while the wrinkled pea seed allele (r) isrecessive. A heterozygous round-seeded pea plant is crossed with a wrinkle-seeded peaplant. Use a Punnett Square to solve the following: a. Determine the predicted genotype ratio of the offspring. b. Determine the predicted phenotype ratio of the offspring. c. If this cross produced 50 plants, how many plants would you predict would bewrinkle-seeded pea plants? please if punnet square needed write down the P G and F1 also thanksarrow_forward
- Please draw a punnett square for thisarrow_forward. In a dihybrid test cross, the following results were obtained: A‑B‑, 121; A‑bb, 107; aaB-, 115; and aabb, 93. Do these data approximate a dihybrid test cross ratio with independent assortment? Complete the following table and answer the related questions. Phenotype O E (O-E) (O-E)2 (O-E)2/E A_B_ 121 A_bb 107 aaB_ 115 aabb 93 Totals X2= Instructor’s Calculation of X2= 4.0367 In interpreting this X2 value, you have ____3_______degrees of freedom. In this case do you accept/reject the hypothesis that these data approximate a dihybrid test cross ratio with independent assortment? What is the probability that the deviations are due to chance alone?arrow_forwardI. In an exotic Peruvian plant, burgundy flowers (B) are dominant to pink flowers (b), green stalks (G) are dominant to yellow (g) and hairy leaves (H) are dominant to smooth leaves (h). What is the probability that the following pair of parents will produce the indicated offspring? Parent 1 = BbGgHh x Parent 2 = BBGghh -> Offspring = BBgghh Punnett squares for each individual trait can help you with this: 000 Parent 1 Parent 2 Probability= (BB) What is the phenotype of BBgghh? Which of the following options are gametes that Parent 1 can produce? Circle the correct one(s). hh BGH Bgh Bb bGh BgH Gg bGH BbGghh (gg) X (hh)arrow_forward
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