Use this information for Exercises 1–4: the preference ballots for an election for the best speaker in a contest are shown. There are three candidates: Peterson (P), Quintana (Q), and Ross (R).
1. Construct a preference table for the results of the election.

To construct: The preference table for the results in the election.
Answer to Problem 1RE
The preference table for the results in the election are listed below.
Number of votes | 5 | 5 | 5 |
First choice | Q | P | R |
Second choice | R | Q | P |
Third choice | P | R | Q |
Explanation of Solution
Given:
The three candidates are Peterson (P), Quintana (Q) and Ross (R).
The preference table of the best speaker in a contest for the election are listed below.
Q | P | R | Q | Q | P | R | P | R | Q | P | R | Q | R | P |
R | Q | P | R | R | Q | P | Q | P | R | Q | P | R | P | Q |
P | R | Q | P | P | R | Q | R | Q | P | R | Q | P | Q | R |
Calculation:
The choices are Peterson (P), Quintana (Q) and Ross (R).
From the ballot preference table, it is noticed that the candidate order QRP occurs 5 times, the candidate order PQR occurs 5 times and the candidate order RPQ occurs 5 times.
That is, the orders of QRP, PQR and RPQ is 5, 5 and 5.
Therefore, the preference table of the results in the election are listed below.
Number of votes | 5 | 5 | 5 |
First choice | Q | P | R |
Second choice | R | Q | P |
Third choice | P | R | Q |
Want to see more full solutions like this?
Chapter 12 Solutions
MATH IN OUR WORLD:ALEKS>CUSTOM<
- Please explain how come of X2(n).arrow_forwardNo chatgpt pls will upvotearrow_forwardFind all solutions of the polynomial congruence x²+4x+1 = 0 (mod 143). (The solutions of the congruence x² + 4x+1=0 (mod 11) are x = 3,4 (mod 11) and the solutions of the congruence x² +4x+1 = 0 (mod 13) are x = 2,7 (mod 13).)arrow_forward
- https://www.hawkeslearning.com/Statistics/dbs2/datasets.htmlarrow_forwardDetermine whether each function is an injection and determine whether each is a surjection.The notation Z_(n) refers to the set {0,1,2,...,n-1}. For example, Z_(4)={0,1,2,3}. f: Z_(6) -> Z_(6) defined by f(x)=x^(2)+4(mod6). g: Z_(5) -> Z_(5) defined by g(x)=x^(2)-11(mod5). h: Z*Z -> Z defined by h(x,y)=x+2y. j: R-{3} -> R defined by j(x)=(4x)/(x-3).arrow_forwardDetermine whether each function is an injection and determine whether each is a surjection.arrow_forward
- Let A = {a, b, c, d}, B = {a,b,c}, and C = {s, t, u,v}. Draw an arrow diagram of a function for each of the following descriptions. If no such function exists, briefly explain why. (a) A function f : AC whose range is the set C. (b) A function g: BC whose range is the set C. (c) A function g: BC that is injective. (d) A function j : A → C that is not bijective.arrow_forwardLet f:R->R be defined by f(x)=x^(3)+5.(a) Determine if f is injective. why?(b) Determine if f is surjective. why?(c) Based upon (a) and (b), is f bijective? why?arrow_forwardLet f:R->R be defined by f(x)=x^(3)+5.(a) Determine if f is injective.(b) Determine if f is surjective. (c) Based upon (a) and (b), is f bijective?arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill
