INTRO.TO PHYSICAL SCIENCE NSU PKG >IC<
INTRO.TO PHYSICAL SCIENCE NSU PKG >IC<
14th Edition
ISBN: 9781305765443
Author: Shipman
Publisher: CENGAGE C
Question
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Chapter 12, Problem 18E

(a)

To determine

Formula for given ionic compound rubidium iodide.

(a)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound rubidium iodide is RbI .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Therefore, Rubidium has a charge of +1 .

An element from the group 7A has an ionic charge 1 . Therefore, Iodine has a charge of 1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Rb1+ combines with I , the formula for the ionic compound is RbI because (1) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound rubidium iodide is RbI .

(b)

To determine

Formula for given ionic compound cesium phosphide.

(b)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound cesium phosphide is Cs3P .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Cesium has a charge of +1 .

An element from the group 5A has an ionic charge 3 . Phosphide has a charge of 3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Cs1+ combines with P3 , the formula for the ionic compound is Cs3P because (3) is used as a subscript for cation and (1) is used as a subscript for the anion.

Conclusion:

Therefore, the formula for ionic compound cesium phosphide is Cs3P .

(c)

To determine

Formula for given ionic compound lithium sulfate.

(c)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound lithium sulfate is Li2SO4 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

An element from the group 1A has an ionic charge +1 . Lithium has a charge of +1 .

Anion sulfate has a charge of 2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Li1+ combines with SO42 , the formula for the ionic compound is Li2SO4 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion SO42 .

Conclusion:

Therefore, the formula for ionic compound lithium sulfate is Li2SO4 .

(d)

To determine

Formula for given ionic compound silver carbonate.

(d)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound silver carbonate is Ag2CO3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Silver has a charge of +1 .

Anion carbonate has a charge of 2 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Ag1+ combines with CO32 , the formula for the ionic compound is Ag2CO3 because (2) is used as a subscript for cation and (1) is used as a subscript for the anion CO32 .

Conclusion:

Therefore, the formula for ionic compound silver carbonate is Ag2CO3 .

(e)

To determine

Formula for given ionic compound zinc phosphate.

(e)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound zinc phosphate is Zn3(PO4)2 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Zinc has a charge of +2 .

Anion phosphate has a charge of 3 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Zn2+ combines with PO43 , the formula for the ionic compound is Zn3(PO4)2 because (3) is used as a subscript for cation and (2) is used as a subscript for the anion PO43 .

Conclusion:

Therefore, the formula for ionic compound zinc phosphate is Zn3(PO4)2 .

(f)

To determine

Formula for given ionic compound aluminium nitrate.

(f)

Expert Solution
Check Mark

Answer to Problem 18E

The formula for ionic compound aluminium nitrate is Al(NO3)3 .

Explanation of Solution

Given Info: Refer to Table 11.6 in the textbook.

Explanation:

Aluminium has a charge of +3 .

Anion nitrate has a charge of 1 .

For a neutral ionic compound, the number of negative and positive charge of ions should be equal. To write the formula of the compound the charge neutrality is maintained. Signs of cation and anion charges are not considered while writing the formula for the compound.

The charge on the metal is used as a subscript for the anion. The charge on the anion is used as a subscript for the cation.

If Al3+ combines with NO31 , the formula for the ionic compound is Al(NO3)3 because (1) is used as a subscript for cation and (3) is used as a subscript for the anion NO31 .

Conclusion:

Therefore, the formula for ionic compound aluminium nitrate is Al(NO3)3 .

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Chapter 12 Solutions

INTRO.TO PHYSICAL SCIENCE NSU PKG >IC<

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