PHYSICAL CHEMISTRY-WEBASSIGN
11th Edition
ISBN: 9780357087411
Author: ATKINS
Publisher: CENGAGE L
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Question
Chapter 12, Problem 12D.3AE
Interpretation Introduction
Interpretation:
The magnetic fields of hyperfine lines and their relative intensities have to be stated for a radical that has two inequivalent protons.
Concept introduction:
EPR stands for electronic paramagnetic resonance. It is used to study species that contain unpaired electrons. EPR can be used to study both solids and liquids. However, the study of the gas phase samples is difficult due to the free rotation of the molecules. The
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6. The formula of the product of the addition of HCN to benzaldehydeis ___.A. C8H7NO; B. C8H6NO; C. C14H11NO; D. C9H9NO; E. C9H8NO
Please include all steps. Thank you!
Predicting the qualitative acid-base properties of salts
Consider the following data on some weak acids and weak bases:
base
acid
K
K
a
name
formula
name
formula
nitrous acid
HNO2 4.5×10
hydroxylamine HONH2 1.1 × 10
8
hypochlorous acid
HCIO
8
3.0 × 10
methylamine CH3NH2 | 4.4 × 10¯
4
Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to
the solution that will have the next lowest pH, and so on.
0.1 M KCIO
solution
PH
choose one
0.1 M NaNO2
0.1 M CH3NH3Br
0.1 M NaBr
choose one ✓
choose one v
✓ choose one
1 (lowest)
☑
2
3
4 (highest)
For this Orgo problem, don't worry about question 3 below it. Please explain your thought process, all your steps, and also include how you would tackle a similar problem. Thank you!
Chapter 12 Solutions
PHYSICAL CHEMISTRY-WEBASSIGN
Ch. 12 - Prob. 12B.1STCh. 12 - Prob. 12B.2STCh. 12 - Prob. 12B.3STCh. 12 - Prob. 12D.1STCh. 12 - Prob. 12A.1DQCh. 12 - Prob. 12A.2DQCh. 12 - Prob. 12A.3DQCh. 12 - Prob. 12A.1AECh. 12 - Prob. 12A.1BECh. 12 - Prob. 12A.2AE
Ch. 12 - Prob. 12A.2BECh. 12 - Prob. 12A.3AECh. 12 - Prob. 12A.3BECh. 12 - Prob. 12A.4AECh. 12 - Prob. 12A.4BECh. 12 - Prob. 12A.5AECh. 12 - Prob. 12A.5BECh. 12 - Prob. 12A.6AECh. 12 - Prob. 12A.6BECh. 12 - Prob. 12A.7AECh. 12 - Prob. 12A.7BECh. 12 - Prob. 12A.8AECh. 12 - Prob. 12A.8BECh. 12 - Prob. 12A.9AECh. 12 - Prob. 12A.9BECh. 12 - Prob. 12A.1PCh. 12 - Prob. 12A.3PCh. 12 - Prob. 12B.1DQCh. 12 - Prob. 12B.2DQCh. 12 - Prob. 12B.3DQCh. 12 - Prob. 12B.4DQCh. 12 - Prob. 12B.5DQCh. 12 - Prob. 12B.1AECh. 12 - Prob. 12B.1BECh. 12 - Prob. 12B.2AECh. 12 - Prob. 12B.2BECh. 12 - Prob. 12B.3AECh. 12 - Prob. 12B.3BECh. 12 - Prob. 12B.4AECh. 12 - Prob. 12B.4BECh. 12 - Prob. 12B.5AECh. 12 - Prob. 12B.5BECh. 12 - Prob. 12B.6AECh. 12 - Prob. 12B.6BECh. 12 - Prob. 12B.7AECh. 12 - Prob. 12B.7BECh. 12 - Prob. 12B.8AECh. 12 - Prob. 12B.8BECh. 12 - Prob. 12B.9AECh. 12 - Prob. 12B.9BECh. 12 - Prob. 12B.10AECh. 12 - Prob. 12B.10BECh. 12 - Prob. 12B.11AECh. 12 - Prob. 12B.11BECh. 12 - Prob. 12B.12AECh. 12 - Prob. 12B.12BECh. 12 - Prob. 12B.13AECh. 12 - Prob. 12B.13BECh. 12 - Prob. 12B.14AECh. 12 - Prob. 12B.14BECh. 12 - Prob. 12B.1PCh. 12 - Prob. 12B.2PCh. 12 - Prob. 12B.3PCh. 12 - Prob. 12B.5PCh. 12 - Prob. 12B.6PCh. 12 - Prob. 12B.7PCh. 12 - Prob. 12B.8PCh. 12 - Prob. 12B.9PCh. 12 - Prob. 12C.1DQCh. 12 - Prob. 12C.2DQCh. 12 - Prob. 12C.3DQCh. 12 - Prob. 12C.4DQCh. 12 - Prob. 12C.5DQCh. 12 - Prob. 12C.1AECh. 12 - Prob. 12C.1BECh. 12 - Prob. 12C.2AECh. 12 - Prob. 12C.2BECh. 12 - Prob. 12C.3AECh. 12 - Prob. 12C.3BECh. 12 - Prob. 12C.4AECh. 12 - Prob. 12C.4BECh. 12 - Prob. 12C.5AECh. 12 - Prob. 12C.5BECh. 12 - Prob. 12C.4PCh. 12 - Prob. 12C.5PCh. 12 - Prob. 12C.6PCh. 12 - Prob. 12C.10PCh. 12 - Prob. 12D.1DQCh. 12 - Prob. 12D.2DQCh. 12 - Prob. 12D.1AECh. 12 - Prob. 12D.1BECh. 12 - Prob. 12D.2AECh. 12 - Prob. 12D.2BECh. 12 - Prob. 12D.3AECh. 12 - Prob. 12D.3BECh. 12 - Prob. 12D.4AECh. 12 - Prob. 12D.4BECh. 12 - Prob. 12D.5AECh. 12 - Prob. 12D.5BECh. 12 - Prob. 12D.6AECh. 12 - Prob. 12D.6BECh. 12 - Prob. 12D.1PCh. 12 - Prob. 12D.2PCh. 12 - Prob. 12D.4PCh. 12 - Prob. 12D.5PCh. 12 - Prob. 12D.6PCh. 12 - Prob. 12D.7PCh. 12 - Prob. 12D.8PCh. 12 - Prob. 12.3IACh. 12 - Prob. 12.4IA
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Similar questions
- Using the general properties of equilibrium constants At a certain temperature, the equilibrium constant K for the following reaction is 0.84: H2(g) + 2(g) 2 HI(g) = Use this information to complete the following table. Suppose a 34. L reaction vessel is filled with 0.79 mol of HI. What can you say about the composition of the mixture in the vessel at equilibrium? There will be very little H2 and 12. ☐ x10 There will be very little HI. Neither of the above is true. What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 HI(g) H₂(9)+12(9) K = What is the equilibrium constant for the following reaction? Be sure your answer has the correct number of significant digits. 2 H2(g)+212(9) 4 HI(g) K = ☐ ☑arrow_forwardPredicting the qualitative acid-base properties of salts Consider the following data on some weak acids and weak bases: base acid Κα Kb name formula name formula hydrocyanic acid - 10 HCN 4.9 × 10 pyridine C₂H₂N 1.7 × 10 9 acetic acid HCH3CO2 1.8 × 10 5 hydroxylamine HONH2 1.1 × 10¯ 8 Use this data to rank the following solutions in order of increasing pH. In other words, select a '1' next to the solution that will have the lowest pH, a '2' next to the solution that will have the next lowest pH, and so on. 0.1 M KCN solution pH choose one ✓ 0.1 M C5H5NHCI choose one ✓ 0.1 M NaCH3CO2 choose one ✓ 0.1 M HONH3Br ✓ choose one 1 (lowest) 2 3 4 (highest)arrow_forwardFor this question please solve the first question. Please explain your thought process, the steps you took, and how you would tackle a similar problem. Thank you for your help!arrow_forward
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