Chapter 12, Problem 12.9P

Interpretation Introduction

Interpretation:

The method to prepare of $\text{500 mL}$ of $0.250{\text{ M C}}_{\text{12}}{\text{H}}_{\text{22}}{\text{O}}_{11}$ has to be explained.

Concept Introduction:

The formula to evaluate moles from molarity is given as follows:

  $n=MV$

Here,

$M$ denotes molarity.

$n$ denotes number of moles.

$V$ denotes volume.

The formula to convert mass in gram to moles is as follows:

  $\text{Mass}=\left(\text{Number of moles}\right)\left(\text{Molar mass}\right)$