
Concept explainers
(a)
To determine: The hybridization of orbitals at each carbon atom and the angles present between the bonds.
(b)
To determine: The structure of polypropylene according to the given three conditions.
(i)
To determine: The structure of polypropylene in which all CH3 groups lies on the same side of the plane of the paper.
(ii)
To determine: The structure of polypropylene in which the CH3 groups lie on the alternating sides of the plane of the paper.
(iii)
To determine: The structure of polypropylene in which the CH3 groups are randomly distributed on either side of the plane of the paper; the form expected to have the highest crystallinity and melting point and the one that is expected to have the lowest.
(c)
To determine: The difference between polypropylene and polyester on the basis of their intermolecular interactions with water.

Want to see the full answer?
Check out a sample textbook solution
Chapter 12 Solutions
CHM 101 VOL 1 2014 >IC<
- The photolysis of H3C–N=N–C2H5 involves the breaking of the single bonds shown. According to this, in addition to N2, what products would be obtained primarily if the reaction were carried out in the gas phase or in solution in an inert solvent?arrow_forwardGiven a keto-enol tautomerization reaction, which is greatly influenced by the type of solvent, indicate which of the following solvent properties cannot be considered a "solvent effect"?(A) Dielectric constant(B) Polarity(C) Hydrogen bonding capacity(D) Temperaturearrow_forwardIn solution reactions, what does "solvent effect" mean?arrow_forward
- How to solvearrow_forwardIndicate the concentration and ionic strength ranges to which the Debye-Huckel equation can be applied. And the Davies equation?arrow_forwardIf the ionic strength (I) of a solution is very low, the Debye-Huckel equation is used. If I is higher, the Davies equation is used. What is the correct value for I to use one or the other?arrow_forward
- In both the Debye-Huckel equation and the Davies equation, there is a constant A. I see that sometimes it appears as 0.51 and other times as 1.02. Explain why one or the other value is used.arrow_forwardThe two equations are forms of the Davies equation, used in thermodynamics for activity coefficients: ال log Y₁ = -Az² - 0,31 log = Az² - 0,31 1 + √Ĩ 1 + √√ k These equations are consistent and imply that Yi = Is this last equation correct? karrow_forwardThe two equations are forms of the Davies equation, used in thermodynamics for activity coefficients: ال log Y₁ = -Az² - 0,31 log = Az² - 0,31 1 + √Ĩ 1 + √√ k These equations are consistent and imply that Yi = Is this last equation correct? karrow_forward
- For the Davies equation, both expressions are correct: log Y₁ = -Az² √i - 0,31 1 + √ k log- = Az - 0,31 k 1 + √Ĩarrow_forwardk In Davies' equation log y₁ = log- log y₁ = log | = -Az² + ✓// k A is a constant that always equals 1.02. Correct? - 0,31arrow_forwardIndicate whether the equality is true Yi How is it obtained? k%arrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY





