(a) Explanation Given information: The height of the water in the open tank at point 1 is 10.0 m , the height of the water at points 2 and 3 is 2.00 m , the cross-sectional area of the pipe at point 2 is 0.0480 m 2 and at point 3 is 0.0160 m 2 , the area of the tank is very large in comparison with the cross-section area of the pipe, the flow of the water is steady and the Bernoulli’s equation is applicable. The flow of water is steady and it is incompressible. The velocity of the water at the point 1 is 0 , as the area of the open tank at point 1 is very large compared to the cross-sectional area of the pipe at point 2 . Apply Bernoulli’s equation at point 1 and 3 , to calculate the formula for velocity of water through the pipe at point 3 . v 3 = 2 g ( h 1 − h 3 ) (I) v 3 is the velocity of water through the pipe at point 3 . h 1 is the height of the water in the open tank at point 1 . h 3 is the height of the water through the pipe at points 3 . g is the acceleration due to gravity. Formula to calculate the discharge rate of the water through the pipe at point 3 is, Q = a 3 × v 3 Q is the discharge rate of the water through the pipe at point 2 . a 2 is the cross-section area of the pipe (b) To determine The gauge pressure at point. 2 .

University Physics with Modern Physics, Books a la Carte Edition; Modified MasteringPhysics with Pearson eText -- ValuePack Access Card -- for ... eText -- Valuepack Access Card (14th Edition)

14th Edition

ISBN: 9780134308142

Author: Hugh D. Young, Roger A. Freedman

Publisher: PEARSON

See similar textbooks

Concept explainers

Variation of pressure

From the equation of pressure, pressure is directly proportional to the applied force.

Question

Chapter 12, Problem 12.81P

(a)

To determine

The discharge rate of the water at point 3 .

(b)

To determine

The gauge pressure at point. 2 .

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 12, Problem 12.80P

Chapter 12, Problem 12.82P

Students have asked these similar questions

Two complex values are z1=8 + 8i, z2=15 + 7 i. z1∗ and z2∗ are the complex conjugate values. Any complex value can be expessed in the form of a+bi=reiθ. Find r and θ for (z1-z∗2)/z1+z2∗. Find r and θ for (z1−z2∗)z1z2∗ Please show all steps

An electromagnetic wave is traveling through vacuum in the positive x direction. Its electric field vector is given by E=E0sin⁡(kx−ωt)j^,where j^ is the unit vector in the y direction. If B0 is the amplitude of the magnetic field vector, find the complete expression for the magnetic field vector B→ of the wave. What is the Poynting vector S(x,t), that is, the power per unit area associated with the electromagnetic wave described in the problem introduction? Give your answer in terms of some or all of the variables E0, B0, k, x, ω, t, and μ0. Specify the direction of the Poynting vector using the unit vectors i^, j^, and k^ as appropriate. Please explain all steps

Another worker is performing a task with an RWL of only 9 kg and is lifting 18 kg, giving him an LI of 2.0 (high risk). Questions:What is the primary issue according to NIOSH?Name two factors of the RWL that could be improved to reduce risk.If the horizontal distance is reduced from 50 cm to 30 cm, how does the HM change and what effect would it have?

Chapter 12 Solutions

University Physics with Modern Physics, Books a la Carte Edition; Modified MasteringPhysics with Pearson eText -- ValuePack Access Card -- for ... eText -- Valuepack Access Card (14th Edition)

Ch. 12.1 - Rank the following objects in order from highest...Ch. 12.2 - Mercury is less dense at high temperatures than at...Ch. 12.3 - You place a container of seawater on a scale and...Ch. 12.4 - A maintenance crew is working on a section of a...Ch. 12.5 - Which is the most accurate statement of Bernoullis...Ch. 12.6 - How much more thumb pressure must a nurse use to...Ch. 12 - A cube of oak wood with very smooth faces normally...Ch. 12 - A rubber hose is attached to a funnel, and the...Ch. 12 - Comparing Example 12.1 (Section 12.1) and Example...Ch. 12 - Prob. 12.4DQ

Knowledge Booster

Learn more about

Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.