Applied Fluid Mechanics
Applied Fluid Mechanics
7th Edition
ISBN: 9780133414622
Author: UNTENER
Publisher: YUZU
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Chapter 12, Problem 12.7PP

Solve Problem 12.4 using the Cross technique.

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Example-1: l D A uniform rotor of length 0.6 m and diameter 0.4 m is made of steel (density 7810 kg/m³) is supported by identical short bearings of stiffness 1 MN/m in the horizontal and vertical directions. If the distance between the bearings is 0.7 m, determine the natural frequencies and plot whirl speed map. Solution: B
find the laplace transform for the flowing function 2(1-e) Ans. F(s)=- S 12) k 0 Ans. F(s)= k s(1+e) 0 a 2a 3a 4a 13) 2+ Ans. F(s)= 1 s(1+e") 3 14) f(t)=1, 0
Find the solution of the following Differential Equations Using Laplace Transforms 1) 4y+2y=0. y(0)=2. y'(0)=0. 2) y+w²y=0, (0)=A, y'(0)=B. 3) +2y-8y 0. y(0)=1. y'(0)-8. 4)-2-3y=0, y(0)=1. y'(0)=7. 5) y-ky'=0, y(0)=2, y'(0)=k. 6) y+ky'-2k²y=0, y(0)=2, y'(0) = 2k. 7) '+4y=0, y(0)=2.8 8) y+y=17 sin(21), y(0)=-1. 9) y-y-6y=0, y(0)=6, y'(0)=13. 10) y=0. y(0)=4, y' (0)=0. 11) -4y+4y-0, y(0)=2.1. y'(0)=3.9 12) y+2y'+2y=0, y(0)=1, y'(0)=-3. 13) +7y+12y=21e". y(0)=3.5. y'(0)=-10. 14) "+9y=10e". y(0)=0, y'(0)=0. 15) +3y+2.25y=91' +64. y(0)=1. y'(0) = 31.5 16) -6y+5y-29 cos(2t). y(0)=3.2, y'(0)=6.2 17) y+2y+2y=0, y(0)=0. y'(0)=1. 18) y+2y+17y=0, y(0)=0. y'(0)=12. 19) y"-4y+5y=0, y(0)=1, y'(0)=2. 20) 9y-6y+y=0, (0)-3, y'(0)=1. 21) -2y+10y=0, y(0)=3, y'(0)=3. 22) 4y-4y+37y=0, y(0)=3. y'(0)=1.5 23) 4y-8y+5y=0, y(0)=0, y'(0)=1. 24) ++1.25y-0, y(0)=1, y'(0)=-0.5 25) y 2 cos(r). y(0)=2. y'(0) = 0. 26) -4y+3y-0, y(0)=3, y(0) 7. 27) y+2y+y=e y(0)=0. y'(0)=0. 28) y+2y-3y=10sinh(27), y(0)=0. y'(0)=4. 29)…
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