EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
9th Edition
ISBN: 8220103611718
Author: SOBHAN
Publisher: CENGAGE L
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Chapter 12, Problem 12.3P
To determine
Find the shear force required to cause failure.
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The single story building shown in Fig. 2 has an applied uniform load of 300 psf (0.3ksf) including the self weight of the beams and the girders. The roof has a 16 ft x 15 ft opening as shown. 1. Determine the axial loads on Columns C1 and C2 using reactions from the beams supported on the columns. 2. Determine the axial loads on Columns C1 and C2 using the concept of tributary areas.
A built-up beam section is formed by welding 2xL8x6x1 angles to the bottom flange of W36x210 as shown in Fig. 1. Determine the following section properties of the built-up cross section: a. Cross sectional area, A (in2) b. The location of the centroids CG-X and CG-Y id of the built up section from the bottom of angle ( this value is given, so you need to check that you get this value) c. Moments of inertia ICG-X (in4) and ICG-Y (in4) d. Section modulus Sx (bot) (in3) and Sx (top) (in3) e. Radius of gyration rx (in) and ry (in) f. Weight of the built up section, w (lb/ft) (use density of steel = 490 pcf)
g. Surface area of the built-up section, S(ft2/ft)
Chapter 12 Solutions
EBK PRINCIPLES OF GEOTECHNICAL ENGINEER
Ch. 12 - Prob. 12.1PCh. 12 - Prob. 12.2PCh. 12 - Prob. 12.3PCh. 12 - Prob. 12.4PCh. 12 - Prob. 12.5PCh. 12 - Prob. 12.6PCh. 12 - Prob. 12.7PCh. 12 - Prob. 12.8PCh. 12 - Prob. 12.9PCh. 12 - Prob. 12.10P
Ch. 12 - Prob. 12.11PCh. 12 - Prob. 12.12PCh. 12 - Prob. 12.13PCh. 12 - Following are the results of...Ch. 12 - Prob. 12.15PCh. 12 - Prob. 12.16PCh. 12 - Prob. 12.17PCh. 12 - Prob. 12.18PCh. 12 - Prob. 12.19PCh. 12 - Prob. 12.20PCh. 12 - Prob. 12.21PCh. 12 - Prob. 12.22PCh. 12 - Prob. 12.23PCh. 12 - Prob. 12.24PCh. 12 - Prob. 12.1CTP
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- P 20 mm 15 mm 100 mm 200 mm 100 mm 15 mm -450.0 mm- -300.0 mm 300.0 mm -300.0 mm -450.0 mm- 300.0 mm The butt connection shows 8-24mm bolts. Spacing and dimensions are shown in figure PSAD-020. The plate is made of A36 steel. Allowable tensile stress on gross area = 0.6Fy Allowable tensile stress on net area = 0.5Fu Allowable shear stress on net area = 0.3Fu Bolt hole diameter = 26mm Determine the allowable tensile load P based on net area rupture. Determine the allowable tensile load P based on gross area yielding. Determine the allowable tensile load P based on block shear strength. Parrow_forward300 mm P 75 mm -75 mm P I 75 mm 100 mm -125 mm Shown in figure PSAD-022 is a splice connection made of 8-22mm A325 bolts and a PL 300 x 12 mm made of A36 steel, connected back-to-back. The connection joins together two A992 W410X67 (Fy = 50 ksi, Fu = 65 ksi) carrying a tension load P. Assume U = 0.70. Ignore bolt shear failure. Determine the design capacity of the connection based on yielding of the plate. Determine the design capacity of the section based on yielding of the wide flange section. Determine the design capacity of the section based on rupture of the plate. Determine the design capacity of the section based on block shear of the plate.arrow_forwardProperties of L 152 x 152 x 11.1 A = 3280 mm² d = 152 mm t = 11.1 mm x = 41.9 mm Ix=7.33 x 10 mm⭑ Iy = 7.33 x 10 mm Zx=119 x 103 mm³ Sx = 66.5 x 103 mm³ P ° ° ° ° ° ° ° ° P Shown in figure PSAD-021 is a truss joint detail. It makes use of two rows of 22-mm bolts. The members are L 152 x 152 x 11.1 made of A36. The plate connecting the members is a 9mm-thick A36 plate (Fy = 36 ksi, Fu = 58 ksi). Assume that U = 0.85, ignore 85% limit of net area. Determine the effective net area of the section. Determine the allowable capacity of the connection.arrow_forward
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