The Basic Practice of Statistics
8th Edition
ISBN: 9781319057916
Author: Moore
Publisher: MAC HIGHER
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Chapter 12, Problem 12.36E
a.
To determine
To explain: The reason for the
b.
To determine
To find: The probability that a randomly selected student who is studying a language apart from English.
c.
To determine
To find: The probability that a randomly selected student who is studying French, German or Spanish.
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II Consider the following data matrix X:
X1
X2
0.5
0.4
0.2 0.5
0.5
0.5
10.3 10
10.1 10.4
10.1
10.5
What will the resulting clusters be when using the k-Means method with k = 2. In your own words, explain why this result is
indeed expected, i.e. why this clustering minimises the ESS map.
why the answer is 3 and 10?
PS
9 Two films are shown on screen A and screen B at a cinema each evening. The numbers
of people viewing the films on 12 consecutive evenings are shown in the back-to-back
stem-and-leaf diagram.
Screen A (12) Screen B (12)
8
037
34
7 6 4 0 534
74 1645678
92 71689
Key: 116|4 represents 61 viewers for A and 64 viewers for B
A second stem-and-leaf diagram (with rows of the same width as the previous diagram)
is drawn showing the total number of people viewing films at the cinema on each of
these 12 evenings. Find the least and greatest possible number of rows that this second
diagram could have.
TIP
On the evening when 30 people viewed films on screen A, there could have been as few
as 37 or as many as 79 people viewing films on screen B.
Chapter 12 Solutions
The Basic Practice of Statistics
Ch. 12.2 - Prob. 1AYKCh. 12.2 - Prob. 2AYKCh. 12.2 - Prob. 3AYKCh. 12.2 - Prob. 4AYKCh. 12.3 - Prob. 5AYKCh. 12.3 - Prob. 6AYKCh. 12.3 - Prob. 7AYKCh. 12.4 - Prob. 8AYKCh. 12.4 - Prob. 9AYKCh. 12.4 - Prob. 10AYK
Ch. 12.4 - Prob. 11AYKCh. 12.5 - Prob. 12AYKCh. 12.5 - Prob. 13AYKCh. 12.5 - Prob. 14AYKCh. 12.6 - Prob. 15AYKCh. 12.6 - Prob. 16AYKCh. 12.6 - Prob. 17AYKCh. 12.7 - Prob. 18AYKCh. 12.7 - Prob. 19AYKCh. 12.8 - Prob. 21AYKCh. 12 - Prob. 12.22CYSCh. 12 - Prob. 12.23CYSCh. 12 - Prob. 12.24CYSCh. 12 - Prob. 12.25CYSCh. 12 - Prob. 12.26CYSCh. 12 - Prob. 12.27CYSCh. 12 - Prob. 12.28CYSCh. 12 - Prob. 12.29CYSCh. 12 - Prob. 12.30CYSCh. 12 - Prob. 12.31CYSCh. 12 - Prob. 12.32ECh. 12 - Prob. 12.33ECh. 12 - Prob. 12.34ECh. 12 - Prob. 12.35ECh. 12 - Prob. 12.36ECh. 12 - Prob. 12.37ECh. 12 - Prob. 12.38ECh. 12 - Prob. 12.39ECh. 12 - Prob. 12.40ECh. 12 - Prob. 12.41ECh. 12 - Prob. 12.42ECh. 12 - Prob. 12.43ECh. 12 - Prob. 12.44ECh. 12 - Prob. 12.45ECh. 12 - Prob. 12.46ECh. 12 - Prob. 12.47ECh. 12 - Prob. 12.48ECh. 12 - Prob. 12.49ECh. 12 - Prob. 12.50ECh. 12 - Prob. 12.51ECh. 12 - Prob. 12.52ECh. 12 - Prob. 12.53ECh. 12 - Prob. 12.54ECh. 12 - Prob. 12.55ECh. 12 - Prob. 12.56ECh. 12 - Prob. 12.57ECh. 12 - Prob. 12.58ECh. 12 - Prob. 12.59E
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