Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated. Concept Introduction: Solubility of a gas in liquid is explained by Henry’s law which states – “At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.” It is expressed as, S α P Where, S = Solubility P = Partial pressure Introducing proportionality constant, S = k H P Where, k H is Henry’s constant . Solubility of a same gas at two different pressures can be calculated as, S 2 S 1 = k H P 2 k H P 1 = P 2 P 1
Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated. Concept Introduction: Solubility of a gas in liquid is explained by Henry’s law which states – “At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.” It is expressed as, S α P Where, S = Solubility P = Partial pressure Introducing proportionality constant, S = k H P Where, k H is Henry’s constant . Solubility of a same gas at two different pressures can be calculated as, S 2 S 1 = k H P 2 k H P 1 = P 2 P 1
Solution Summary: The author explains how the solubility of an unknown gas at partial pressure and temperature is calculated by Henry's law.
Given the solubility of an unknown gas at partial pressure and temperature, its solubility at partial pressure 24.6 atm has to be calculated.
Concept Introduction:
Solubility of a gas in liquid is explained by Henry’s law which states –
“At a constant temperature, the amount of a gas dissolved in a given volume of liquid is directly proportional to the partial pressure of the gas that is in equilibrium with the liquid.”
It is expressed as,
SαP
Where,
S = SolubilityP = Partial pressure
Introducing proportionality constant,
S=kHP
Where,
kH is Henry’s constant.
Solubility of a same gas at two different pressures can be calculated as,
Denote the dipole for the indicated bonds in the following molecules.
H3C
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CH3
B
F-CCl 3
Br-Cl
H3C Si(CH3)3
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OH
НО.
HO
HO
OH
vitamin C
CH3
For the SN2 reaction, draw the major organic product and select the correct (R) or (S) designation around the stereocenter
carbon in the organic substrate and organic product. Include wedge-and-dash bonds and draw hydrogen on a stereocenter.
Η
1
D
EN
Select Draw Templates More
C
H
D
N
Erase
Q9: Explain why compound I is protonated on O while compound II is protonated on N.
NH2
NH2
I
II
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