NEW PERSP.ON COMP.CONCEPTS-PACKAGE
17th Edition
ISBN: 9781337761116
Author: Carey
Publisher: CENGAGE L
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Chapter 12, Problem 11CP4
a.
Program Plan Intro
To create the defineColumns() function and add command to append a new embedded style sheet to the document head in the function.
b.
Program Plan Intro
To add the given style rule to display a pointer cursor over the column headings in the above defined function.
c.
Program Plan Intro
To add the given style rule to the column headings that should display an icon that indicates they are sortable in the above defined function.
d.
Program Plan Intro
To add the given style rule to change the icon for the first column heading to a ▲ in the above defined function.
e.
Program Plan Intro
To create a for loop that loops through the th elements in the table heading and
- Store the text content of the table heading cell in the dataCategories array
- Add an event handler that calls the columnSort() function.
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using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
using r language
Chapter 12 Solutions
NEW PERSP.ON COMP.CONCEPTS-PACKAGE
Ch. 12.2 - Prob. 1QCCh. 12.2 - Prob. 2QCCh. 12.2 - Prob. 3QCCh. 12.2 - Prob. 4QCCh. 12.2 - Prob. 5QCCh. 12.2 - Prob. 6QCCh. 12.3 - Prob. 1QCCh. 12.3 - Prob. 2QCCh. 12 - Prob. 1RACh. 12 - Prob. 2RA
Ch. 12 - Prob. 3RACh. 12 - Prob. 4RACh. 12 - Prob. 5RACh. 12 - Prob. 6RACh. 12 - Prob. 7RACh. 12 - Prob. 8RACh. 12 - Prob. 9RACh. 12 - Prob. 10RACh. 12 - Prob. 11RACh. 12 - Prob. 12RACh. 12 - Prob. 13RACh. 12 - Prob. 1CP1Ch. 12 - Prob. 2CP2Ch. 12 - Prob. 3CP2Ch. 12 - Prob. 4CP2Ch. 12 - Prob. 5CP2Ch. 12 - Prob. 4CP3Ch. 12 - Prob. 20CP3Ch. 12 - Prob. 3CP4Ch. 12 - Prob. 4CP4Ch. 12 - Prob. 5CP4Ch. 12 - Prob. 6CP4Ch. 12 - Prob. 7CP4Ch. 12 - Prob. 8CP4Ch. 12 - Prob. 9CP4Ch. 12 - Prob. 10CP4Ch. 12 - Prob. 11CP4Ch. 12 - Prob. 12CP4Ch. 12 - Prob. 13CP4Ch. 12 - Prob. 14CP4
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