Consider the hypothetical reaction A + B +2C → 2 D + 3E In a study of this reaction three experiments were run at the same temperature. The rate is defined as −∆[B]/∆ t . Experiment 1: [A] 0 = 2.0 M [B] 0 = 1.0 × 10 −3 M [C] 0 = 1.0 M [B] (mol/L) Time(s) 2.7 × 10 −4 1.0 × 10 5 1.6 × 10 −4 2.0 × 10 5 1.1 × 10 −4 3.0 × 10 5 8.5 × 10 −5 4.0 × 10 5 6.9 × 10 −5 5.0 × 10 5 5.8 × 10 −5 6.0 × 10 5 Experiment 2: [A] 0 = 1.0 × 10 −2 M [B] 0 = 3.0 M [C] 0 = 1.0 M [A] (mol/L) Time(s) 8.9 × 10 −3 1.0 7.1 × 10 −3 3.0 5.5 × 10 −3 5.0 3.8 × 10 −3 8.0 2.9 × 10 −3 10.0 2.0 × 10 −3 13.0 Experiment 3: [A] 0 = 10.0 M [B] 0 = 5.0 M [C] 0 = 5.0 × 10 −1 M [C] (mol/L) Time(s) 0.43 1.0 × 10 −2 0.36 2.0 × 10 −2 0.29 3.0 × 10 −2 0.22 4.0 × 10 −2 0.15 5.0 × 10 −2 0.08 6.0 × 10 −2 Write the rate law for this reaction, and calculate the value of the rate constant.
Consider the hypothetical reaction A + B +2C → 2 D + 3E In a study of this reaction three experiments were run at the same temperature. The rate is defined as −∆[B]/∆ t . Experiment 1: [A] 0 = 2.0 M [B] 0 = 1.0 × 10 −3 M [C] 0 = 1.0 M [B] (mol/L) Time(s) 2.7 × 10 −4 1.0 × 10 5 1.6 × 10 −4 2.0 × 10 5 1.1 × 10 −4 3.0 × 10 5 8.5 × 10 −5 4.0 × 10 5 6.9 × 10 −5 5.0 × 10 5 5.8 × 10 −5 6.0 × 10 5 Experiment 2: [A] 0 = 1.0 × 10 −2 M [B] 0 = 3.0 M [C] 0 = 1.0 M [A] (mol/L) Time(s) 8.9 × 10 −3 1.0 7.1 × 10 −3 3.0 5.5 × 10 −3 5.0 3.8 × 10 −3 8.0 2.9 × 10 −3 10.0 2.0 × 10 −3 13.0 Experiment 3: [A] 0 = 10.0 M [B] 0 = 5.0 M [C] 0 = 5.0 × 10 −1 M [C] (mol/L) Time(s) 0.43 1.0 × 10 −2 0.36 2.0 × 10 −2 0.29 3.0 × 10 −2 0.22 4.0 × 10 −2 0.15 5.0 × 10 −2 0.08 6.0 × 10 −2 Write the rate law for this reaction, and calculate the value of the rate constant.
Solution Summary: The author explains the rate law for the given reaction and the value of rate constant. The order of the reaction is the number or the index raise to the concentration term with respect to each component.
8
00
6
= 10
10
Decide whether each of the molecules in the table below is stable, in the exact form in which it is drawn, at pH = 11.
If
you decide at least one molecule is not stable, then redraw one of the unstable molecules in its stable form below the table. (If more than
unstable, you can pick any of them to redraw.)
Check
OH
stable
HO
stable
Ounstable
unstable
O
OH
stable
unstable
OH
80
F6
F5
stable
Ounstable
X
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Sub
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ཀྭ་
A
F7
매
F8
F9
4
F10
Just try completing it and it should be straightforward according to the professor and TAs.
The grading is not on correctness, so if you can just get to the correct answers without perfectionism that would be great. They care about the steps and reasoning and that you did something. I asked for an extension, but was denied the extension.
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Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell