Explanation Given Information: The three lines are y = 2 x + 1 , y = x + 1 and y = 0.5 x + 1 . Graph: Consider the provided equation of lines, y = 2 x + 1 , y = x + 1 and y = 0.5 x + 1 Now, graph the lines using the TI- 83 graphing calculator as follows: Step 1: Open Ti-83 calculator and press ON key. Step 2: Press “ Y = ” key and insert the equations of the lines as, Y 1 = 2 X+1 Y 2 = X+1 Y 3 = 0.5 X + 1 Step 3: Press WINDOW key and set as: Xmin = − 3 Xmax = 3 Xscl = 1 Ymin = − 3 And Ymax = 3 Yscl = 1 Step 4: Then press the “GRAPH” key. A window showing the graph of the three lines will appear as, To identify the lines substitute x = 2 in all the lines y = 2 x + 1 , y = x + 1 and y = 0

Finite Mathematics & Its Applications (12th Edition)

12th Edition

ISBN: 9780134507125

Author: Goldstein

Publisher: PEARSON

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Chapter 1.2, Problem 100E

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To graph: The three lines y=2x+1,y=x+1 and y=0.5x+1 together, and identify each line without using TRACE.

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Chapter 1.2, Problem 99E

Chapter 1.2, Problem 101E

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Finite Mathematics & Its Applications (12th Edition)

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To graph: The three lines y = 2 x + 1 , y = x + 1 and y = 0.5 x + 1 together, and identify each line without using TRACE.

Solution Summary: The author explains how to graph the lines using the TI-83 graphing calculator.

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To graph: The three lines y=2x+1,y=x+1 and y=0.5x+1 together, and identify each line without using TRACE.

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