(a) Explanation Write the expression for Maxwell relation. ( ∂ v ∂ T ) P = ( v 2 − v 1 T 2 − T 1 ) P (I) Here, the change in volume is ∂ v , the change in temperature is ∂ T , the volume at initial state is v 1 , the volume at final state is v 2 , the temperature at initial state is T 1 and the temperature at final state is T 2 . Write the expression for change in specific entropy with respect to pressure at constant pressure. ( ∂ s ∂ P ) P = ( s 2 − s 1 P 2 − P 1 ) P (II) Here, the specific entropy at initial state is s 1 and the specific entropy at final state is s 2 . Write the expression for Maxwell relation. ( ∂ v ∂ T ) p = ( ∂ s ∂ p ) T (III) Conclusion: Refer to the Table A-4 “Properties of superheated water vapour” to obtain the value of temperature and specific volume as 400 ° F and 4.934 ft 3 / lb , 500 ° F and 5.587 ft 3 / lb , 600 ° F and 6.216 ft 3 / lb , 700 ° F and 6.834 ft 3 / lb , 800 ° F and 7.445 ft 3 / lb at a pressure of 100 lbf / in 2 . The table below show the temperature and specific volume at a pressure of 100 lbf / in 2 . T ( ° F ) v ( ft 3 / lb ) 400 4.934 500 5.587 600 6.216 700 6.834 800 7.445 The graph below shows the v - T diagram at a pressure of 100 lbf / in . 2 . Figure-(1) Substitute 7.445 ( ft 3 / lb ) for v 2 , 4.934 ( ft 3 / lb ) for v 1 , 800 ° F for T 2 and 400 ° F for T 1 in Equation (I). ( ∂ V ∂ T ) P = ( 7.445 ft 3 / lb − 4.934 ft 3 / lb 800 ° F − 400 ° F ) = ( 7.445 ft 3 / lb − 4.934 ft 3 / lb ( 800 ° F + 460 ) °R − ( 400 ° C+460 ) °R ) = ( 2.511 ft 3 / lb 400 ° R ) = 6.277 × 10 − 3 ft 3 / lb ⋅ ° R Refer to the Table A-4E “Properties of superheated water vapour” to obtain the value of pressure and enthalpy as 60 lbf / in 2 and 1.8165 Btu / lb ⋅ ° R , 80 lbf / in 2 and 1 (b) To determine The consistency of the refrigerant 134 a at 40 lbf / in 2 and 100 ° F .

Fundamentals of Engineering Thermodynamics, Binder Ready Version

8th Edition

ISBN: 9781118820445

Author: Michael J. Moran, Howard N. Shapiro, Daisie D. Boettner, Margaret B. Bailey

Publisher: WILEY

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Chapter 11.9, Problem 25P

(a)

To determine

The consistency of steam table at 100 lbf/in2 and 600 °F.

(b)

To determine

The consistency of the refrigerant 134a at 40 lbf/in2 and 100 °F.

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Chapter 11.9, Problem 24P

Chapter 11.9, Problem 26P

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Chapter 11 Solutions

Fundamentals of Engineering Thermodynamics, Binder Ready Version

Ch. 11.9 - Prob. 1E Ch. 11.9 - Prob. 2E Ch. 11.9 - 3. What is an advantage of using the Redlich–Kwong...Ch. 11.9 - To determine the specific volume of superheated...Ch. 11.9 - Prob. 5E Ch. 11.9 - Prob. 6E Ch. 11.9 - Prob. 7E Ch. 11.9 - Prob. 8E Ch. 11.9 - Prob. 9E Ch. 11.9 - Prob. 10E

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The consistency of steam table at 100 lbf / in 2 and 600 ° F .

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The consistency of steam table at 100 lbf/in2 and 600 °F.

The consistency of the refrigerant 134a at 40 lbf/in2 and 100 °F.

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Chapter 11 Solutions