Explanation Write the given expression of differential pressure. d p = 2 ( v − b ) R T d v + ( v − b ) 2 R T 2 d T (I) d p = − R T ( v − b ) 2 d v + R v − b d T (II) Here, the gas constant is R , the differential pressure is d p , the differential specific volume is d v , the differential temperature is d T , the temperature is T , the specific volume is v and the constant is b . Consider the Equation (I). Integrate the Equation (I). ∫ d p = ∫ 2 ( v − b ) R T d v + ∫ ( v − b ) 2 R T 2 d T P = 2 R T ∫ ( v − b ) d v + ( v − b ) 2 R ∫ 1 T 2 d T P = 2 R T [ ( v − b ) 2 2 ] + ( v − b ) 2 R ( − 1 T )

Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

8th Edition

ISBN: 9781118957219

Author: Michael J. Moran, Howard N. Shapiro

Publisher: WILEY

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Appendices to accompany Fundamentals of Engineering Thermodynamics, 8e

Ch. 11.9 - Prob. 1E Ch. 11.9 - Prob. 2E Ch. 11.9 - 3. What is an advantage of using the Redlich–Kwong...Ch. 11.9 - To determine the specific volume of superheated...Ch. 11.9 - Prob. 5E Ch. 11.9 - Prob. 6E Ch. 11.9 - Prob. 7E Ch. 11.9 - Prob. 8E Ch. 11.9 - Prob. 9E Ch. 11.9 - Prob. 10E

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