Explanation Given: The provided function is f ( x ) = 20 x + 5 and point is ( 1 , 5 ) . Formula used: If f ( x ) be any function and if the slope of the tangent to the function at points ( x 1 , y 1 ) is t then the value of slope is given by: t = d d x f ( x ) ( x 1 , y 1 ) and, the equation of the tangent to the function at points ( x 1 , y 1 ) is given by: y − y 1 = t ( x − x 1 ) and, If f ( x ) = [ u ( x ) ] n for any real number n . According to Generalized power rule, the derivative of the function f ( x ) is, f ′ ( x ) = n ⋅ [ u ( x ) ] n − 1 u ′ ( x ) Here, u ( x ) is the function of x and u ′ ( x ) is the derivative of the function u ( x ) . Calculation: Consider the given equation. f ( x ) = 20 x + 5 Differentiate the above equation with respect to x by using generalized power rule

Mathematics With Applications, Loose-leaf Edition Plus Mylab Math With Pearson Etext -- 18-week Access Card Package (12th Edition)

12th Edition

ISBN: 9780135998304

Author: Margaret L. Lial, Tom Hungerford, John P. Holcomb, Bernadette Mullins

Publisher: PEARSON

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Chapter 11.7, Problem 51E

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To calculate: The equation of the tangent line to the graph of f(x)=20x+5 at (1,5).

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Chapter 11.7, Problem 50E

Chapter 11.7, Problem 52E

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Chapter 11 Solutions

Mathematics With Applications, Loose-leaf Edition Plus Mylab Math With Pearson Etext -- 18-week Access Card Package (12th Edition)

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The equation of the tangent line to the graph of f ( x ) = 20 x + 5 at ( 1 , 5 ) .

Solution Summary: The author explains the equation of the tangent line to the graph of f(x)=sqrt20x+5 and point is

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To calculate: The equation of the tangent line to the graph of f(x)=20x+5 at (1,5).

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Chapter 11 Solutions