Explanation Given: Expression is given as ( 1.001 ) 5 . It can be written as ( 1 + 0.001 ) 5 = ( 1 + 10 − 3 ) 5 Formula used: The Binomial Theorem: Let x and a be real numbers. For any positive integer n , we have ( x + a ) n = ( n 0 ) x n + ( n 1 ) a x n − 1 + ⋯ + ( n j ) a j x n − j + ⋯ + ( n n ) a n ( x + a ) n = ∑ k = 0 n ( n k ) x n − j a j Here x = 1 , a = 10 − 3 and n = 5 . Applying Binomial theorem. ( 1 + 10 − 3 ) 5 = ( 5 0 ) ( 1 ) 5 + ( 5 1 ) ( 10 − 3 ) ( 1 ) 4 + ( 5 2 ) ( 10 − 3 ) 2 ( 1 ) 3 + ( 5 3 ) ( 10 −

Pearson eText for Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry -- Instant Access (Pearson+)

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Author: Michael Sullivan, Michael Sullivan

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Chapter 11.5, Problem 43AYU

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To find: The numerical value of ${(1.001)}^{5}$ correct to five decimal places.

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Chapter 11.5, Problem 42AYU

Chapter 11.5, Problem 44AYU

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Pearson eText for Precalculus: Concepts Through Functions, A Unit Circle Approach to Trigonometry -- Instant Access (Pearson+)

Ch. 11.1 - For the function f( x )= x1 x , find f( 2 ) and f(...Ch. 11.1 - True or False A function is a relation between two...Ch. 11.1 - Prob. 3AYU Ch. 11.1 - True or False The notation a5 represents the fifth...Ch. 11.1 - True or False If n2 is am integer, then...Ch. 11.1 - The sequence , is an example of...Ch. 11.1 - The notation a 1 + a 2 + a 3 ++ a n = k=1 n a k...Ch. 11.1 - ______. (a) (b) (c) (d) ...Ch. 11.1 - In Problems 11-16, evaluate each factorial...Ch. 11.1 - In Problems 11-16, evaluate each factorial...

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