Explanation Given: The provided logarithmic equation is: log 8 x + log 8 ( x − 2 ) = 1 . Formula Used: Logarithm formula for multiplication, log a ( m ⋅ n ) = log a ( m ) + log a ( n ) . Here, a , m and n are the positive real numbers and a ≠ 1 . Conversion of logarithmic expression in to exponential expression as: If the logarithmic expression log a b = c , then the exponential expression is expressed as a c = b . Here, b is the positive real numbers and c is the real number. Calculation: Consider the expression, log 8 x + log 8 ( x − 2 ) = 1 . Use the logarithm formula for multiplication. log 8 [ ( x ) ( x − 2 ) ] = 1 log 8 ( x 2 − 2 x ) = 1 Convert logarithmic expression in to exponential expression. ( x 2 − 2 x ) = 8 1

Pearson eText for Intermediate Algebra -- Instant Access (Pearson+)

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ISBN: 9780137553464

Author: John Tobey, Jeffrey Slater

Publisher: PEARSON+

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Chapter 11.5, Problem 14E

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Chapter 11.5, Problem 13E

Chapter 11.5, Problem 15E

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Chapter 11 Solutions

Pearson eText for Intermediate Algebra -- Instant Access (Pearson+)

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The solution of logarithmic equation log 8 x + log 8 ( x − 2 ) = 1 and check the solution.

Solution Summary: The author explains the logarithmic equation, which is simplified to underset_x=4.

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Chapter 11 Solutions