Explanation Given Information: The equation is 1 − 1 3 x − 2 − 1 ( 3 x − 2 ) 2 = 0 . Formula used: The quadratic formula states that for an equation a x 2 + b x + c = 0 , the value of x can be found by using, x = − b ± b 2 − 4 a c 2 a The square of difference of two terms is given by, ( a − b ) 2 = a 2 + b 2 − 2 a b Calculation: Consider the equation, 1 − 1 3 x − 2 − 1 ( 3 x − 2 ) 2 = 0 …… (1) To solve the equation, multiply both side by the least common denominator. The least common denominator is ( 3 x − 2 ) 2 . So, multiply both sides by ( 3 x − 2 ) 2 , ( 3 x − 2 ) 2 ( 1 − 1 3 x − 2 − 1 ( 3 x − 2 ) 2 ) = 0 ⋅ ( 3 x − 2 ) 2 ( 3 x − 2 ) 2 − ( 3 x − 2 ) − 1 = 0 ( 3 x ) 2 + ( 2 ) 2 − 2 ( 3 x ) ( 2 ) − 3 x + 2 − 1 = 0 9 x 2 + 4 − 12 x − 3 x + 1 = 0 Simplify it further, 9 x 2 − 15 x + 5 = 0 Since, it cannot be factorized further, thus, substitute 9 for a , − 15 for b and 5 for c in the quadratic formula, x = − ( − 15 ) ± (

Beginning and Intermediate Algebra (6th Edition)

6th Edition

ISBN: 9780321969163

Author: Margaret L. Lial, John Hornsby, Terry McGinnis

Publisher: PEARSON

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Chapter 11.4, Problem 24E

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To calculate: The solution to the equation, 1−13x−2−1(3x−2)2=0 and check the solution.

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Chapter 11.4, Problem 23E

Chapter 11.4, Problem 25E

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Chapter 11 Solutions

Beginning and Intermediate Algebra (6th Edition)

Ch. 11.1 - Concept Check Answer each question. 1. Which of...Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Solve each equation using the zero-factor...Ch. 11.1 - Prob. 6E Ch. 11.1 - Solve each equation using the zero-factor...Ch. 11.1 - Prob. 8E Ch. 11.1 - Solve each equation using the zero-factor...Ch. 11.1 - Prob. 10E

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The solution to the equation, 1 − 1 3 x − 2 − 1 ( 3 x − 2 ) 2 = 0 and check the solution.

Solution Summary: The author explains the quadratic formula used to solve the equation, 1-13x-2, which states that the value of x can be found by multiplying both sides by the least common denom

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To calculate: The solution to the equation, 1−13x−2−1(3x−2)2=0 and check the solution.

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Chapter 11 Solutions