Explanation Given Information: The given expression is 0.36 = 1 − e 7 k . Formula used: The following steps should be followed: Step 1: first write the primary equation and then take log on both sides. Step 2: After simplifying the logarithmic expression find the value of k . Calculation: Consider the primary equation, 0.36 = 1 − e 7 k Simplify the primary equation: 0.36 = 1 − e 7 k e 7 k = 1 − 0.36 e 7 k = 0.64 Take logarithmic on both sides of the equation e 7 k = 0.64 , log e e 7 k = log e ( 64 100 ) 7 k = log e ( 0

Bundle: Calculus: An Applied Approach, Loose-Leaf Version, 10th + WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term

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ISBN: 9781337604802

Author: Larson

Publisher: CENGAGE L

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Chapter 11.4, Problem 10SWU

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To calculate: The value of k in the given expression 0.36=1−e7k.

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Chapter 11.4, Problem 9SWU

Chapter 11.4, Problem 1E

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Chapter 11 Solutions

Bundle: Calculus: An Applied Approach, Loose-Leaf Version, 10th + WebAssign Printed Access Card for Larson's Calculus: An Applied Approach, 10th Edition, Single-Term

Ch. 11.1 - Checkpoint 1 Worked-out solution available at...Ch. 11.1 - Prob. 2CP Ch. 11.1 - Prob. 3CP Ch. 11.1 - Prob. 4CP Ch. 11.1 - Prob. 1SWU Ch. 11.1 - Prob. 2SWU Ch. 11.1 - Prob. 3SWU Ch. 11.1 - Prob. 4SWU Ch. 11.1 - Prob. 5SWU Ch. 11.1 - Prob. 6SWU

Ch. 11.1 - Verifying Solutions In Exercises 112, verify the...Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Prob. 6E Ch. 11.1 - Prob. 7E Ch. 11.1 - Prob. 8E Ch. 11.1 - Verifying Solutions In Exercises 1-12, verify the...Ch. 11.1 - Prob. 10E Ch. 11.1 - Prob. 11E Ch. 11.1 - Prob. 12E Ch. 11.1 - Prob. 13E Ch. 11.1 - Prob. 14E Ch. 11.1 - Determining Solutions In Exercises 1316, determine...Ch. 11.1 - Prob. 16E Ch. 11.1 - Determining Solutions In Exercises 1720, determine...Ch. 11.1 - Prob. 18E Ch. 11.1 - Prob. 19E Ch. 11.1 - Prob. 20E Ch. 11.1 - Prob. 21E Ch. 11.1 - Prob. 22E Ch. 11.1 - Prob. 23E Ch. 11.1 - Prob. 24E Ch. 11.1 - Prob. 25E Ch. 11.1 - Prob. 26E Ch. 11.1 - Prob. 27E Ch. 11.1 - Prob. 28E Ch. 11.1 - Prob. 29E Ch. 11.1 - Prob. 30E Ch. 11.1 - Prob. 31E Ch. 11.1 - Prob. 32E Ch. 11.1 - Prob. 33E Ch. 11.1 - Prob. 34E Ch. 11.1 - Prob. 35E Ch. 11.1 - Prob. 36E Ch. 11.1 - Prob. 37E Ch. 11.1 - Prob. 38E Ch. 11.1 - Prob. 39E Ch. 11.1 - Investment The rate of growth of an investment is...Ch. 11.1 - Prob. 41E Ch. 11.1 - Prob. 42E Ch. 11.1 - Prob. 43E Ch. 11.1 - Prob. 44E Ch. 11.1 - Prob. 45E Ch. 11.1 - Prob. 46E Ch. 11.2 - Checkpoint 1 Worked-out solution available at...Ch. 11.2 - Prob. 2CP Ch. 11.2 - Prob. 3CP Ch. 11.2 - Prob. 4CP Ch. 11.2 - Prob. 5CP Ch. 11.2 - Prob. 6CP Ch. 11.2 - Prob. 1SWU Ch. 11.2 - Prob. 2SWU Ch. 11.2 - Prob. 3SWU Ch. 11.2 - Prob. 4SWU Ch. 11.2 - Prob. 5SWU Ch. 11.2 - Prob. 6SWU Ch. 11.2 - Prob. 7SWU Ch. 11.2 - Prob. 8SWU Ch. 11.2 - Prob. 9SWU Ch. 11.2 - Prob. 10SWU Ch. 11.2 - Prob. 1E Ch. 11.2 - Prob. 2E Ch. 11.2 - Prob. 3E Ch. 11.2 - Prob. 4E Ch. 11.2 - Prob. 5E Ch. 11.2 - Prob. 6E Ch. 11.2 - Prob. 7E Ch. 11.2 - Prob. 8E Ch. 11.2 - Prob. 9E Ch. 11.2 - Prob. 10E Ch. 11.2 - Prob. 11E Ch. 11.2 - Prob. 12E Ch. 11.2 - Prob. 13E Ch. 11.2 - Solving a Differential Equation In Exercises 7-26,...Ch. 11.2 - Prob. 15E Ch. 11.2 - Prob. 16E Ch. 11.2 - Prob. 17E Ch. 11.2 - Prob. 18E Ch. 11.2 - Prob. 19E Ch. 11.2 - Prob. 20E Ch. 11.2 - Prob. 21E Ch. 11.2 - Prob. 22E Ch. 11.2 - Prob. 23E Ch. 11.2 - Prob. 24E Ch. 11.2 - Prob. 25E Ch. 11.2 - Prob. 26E Ch. 11.2 - Prob. 27E Ch. 11.2 - Prob. 28E Ch. 11.2 - Prob. 29E Ch. 11.2 - Prob. 30E Ch. 11.2 - Prob. 31E Ch. 11.2 - Finding a Particular Solution In Exercises 31-38,...Ch. 11.2 - Prob. 33E Ch. 11.2 - Finding a Particular Solution In Exercises 31-38,...Ch. 11.2 - Prob. 35E Ch. 11.2 - Finding a Particular Solution In Exercises 31-38,...Ch. 11.2 - Prob. 37E Ch. 11.2 - Prob. 38E Ch. 11.2 - Prob. 39E Ch. 11.2 - Prob. 40E Ch. 11.2 - Prob. 41E Ch. 11.2 - Prob. 42E Ch. 11.2 - Prob. 43E Ch. 11.2 - Prob. 44E Ch. 11.2 - Radioactive Decay The rate of decomposition of...Ch. 11.2 - Radioactive Decay The rate of decomposition of...Ch. 11.2 - Solve the differential equation. 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The value of k in the given expression 0.36 = 1 − e 7 k .

Solution Summary: The author explains how to calculate the value of k in the given expression 0.36=1-e7k.

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To calculate: The value of k in the given expression 0.36=1−e7k.

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Chapter 11 Solutions