a . Solve the quadratic equation by factoring. u 2 + 10 u + 24 = 0 b. Solve the equation by using substitution. ( y 2 + 5 y ) 2 + 10 ( y 2 + 5 y ) + 24 = 0
a . Solve the quadratic equation by factoring. u 2 + 10 u + 24 = 0 b. Solve the equation by using substitution. ( y 2 + 5 y ) 2 + 10 ( y 2 + 5 y ) + 24 = 0
Solution Summary: The author explains how to calculate the solution of the equation, u2+10u+24=0 by factoring.
a. Solve the quadratic equation by factoring.
u
2
+
10
u
+
24
=
0
b. Solve the equation by using substitution.
(
y
2
+
5
y
)
2
+
10
(
y
2
+
5
y
)
+
24
=
0
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
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Determine if the values of the variables listed are solutions of the system of equations.
2x - y = 4
3x+5y= - 6
x=1, y = 2; (1,-2)
Is (1, 2) a solution of the system of equations?
L
No
Yes
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10. A sound wave's amplitude can be modeled by the function y = −7 sin ((x-1) + 4). Within the interval 0 < x < 12, when does the function have an amplitude
of 4? (Select all that apply.)
9.522 seconds
4.199 seconds
0.522 seconds
1.199 seconds
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