a . Solve the quadratic equation by factoring. u 2 + 10 u + 24 = 0 b. Solve the equation by using substitution. ( y 2 + 5 y ) 2 + 10 ( y 2 + 5 y ) + 24 = 0
a . Solve the quadratic equation by factoring. u 2 + 10 u + 24 = 0 b. Solve the equation by using substitution. ( y 2 + 5 y ) 2 + 10 ( y 2 + 5 y ) + 24 = 0
Solution Summary: The author explains how to calculate the solution of the equation, u2+10u+24=0 by factoring.
a. Solve the quadratic equation by factoring.
u
2
+
10
u
+
24
=
0
b. Solve the equation by using substitution.
(
y
2
+
5
y
)
2
+
10
(
y
2
+
5
y
)
+
24
=
0
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
OR
16 f(x) =
Ef 16
χ
по
x²-2 410 | y = (x+2) + 4
Y-INT: y = 0
X-INT: X=0
VA: x=2
OA: y=x+2
0
X-INT: X=-2
X-INT: y = 2
VA
0
2
whole.
2-2
4
y - (x+2) = 27-270
+
xxx> 2
क्
above OA
(x+2) OA
x-2/x²+0x+0
2
x-2x
2x+O
2x-4
4
X<-1000 4/4/2<0 below Of
y
VA
X=2
X-2
OA
y=x+2
-2
2
(0,0)
2
χ
I need help solving the equation
3x+5=8
What is the domain, range, increasing intervals (theres 3), decreasing intervals, roots, y-intercepts, end behavior (approaches four times), leading coffiencent status (is it negative, positivie?) the degress status (zero, undifined etc ), the absolute max, is there a absolute minimum, relative minimum, relative maximum, the root is that has a multiplicity of 2, the multiplicity of 3.
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