
(a)
To state:
Null hypothesis and alternative hypothesis.

Answer to Problem 8E
Solution:
Null Hypothesis is
Alternative Hypothesis is
Explanation of Solution
Given:
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the
Let the days when no advertisements are played on radio corresponds to poupulation1 and the days when advertisements are played corresponds to population 2. Let
The null hypothesis is that the mean number of customers is not lower on days following no advertisements than the mean number of customers on days following advertisements. The null hypothesis is stated as follows-
Alternative hypothesis-.
Thus, the hypotheses are stated as follows:
(b)
The type of distribution to use for the test statistics and state the level of significance.

Answer to Problem 8E
Solution:
The t-test statistic for equal variances is appropriate and the level of significance for this test is.
Explanation of Solution
Given:
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 11 days following no advertisements, the mean was 17.8 purchasing customers with a standard deviation of 3.5 customers. On 6 days following advertising, the mean was 22.8 purchasing customers with a standard deviation of 2.8 customers. Assume that the population variances are equal.
Given that the difference between two population means when both population variances are unknown but assumed to be equal and random samples drawn are independent. Both the population distributions are approximately normal. The t-test statistic for equal variances is appropriate. The level of significance for this test is
Therefore, the t-test statistic for equal variances is appropriate and the level of significance for this test is
(c)
To calculate:
The test statistic.

Answer to Problem 8E
Solution:
The test statistic is -3.0006.
Explanation of Solution
Given:
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 11 days following no advertisements, the mean was 17.8 purchasing customers with a standard deviation of 3.5 customers. On 6 days following advertising, the mean was 22.8 purchasing customers with a standard deviation of 2.8 customers. Assume that the population variances are equal.
Formula used:
The test statistic for a hypothesis test for two population means is given by
Such that both population standard deviations are unknown and assumed to be equal, the samples taken are independent, simple random samples, and either both
The number of degrees of freedom for the t-distribution of the test statistic is
Calculation:
Given information, the sample means are
The standard deviation for the first sample is
The standard deviation for the second sample is
The test statistic for a given hypothesis test is
From equation
It is given that the null hypothesis for the given proportion is
Thus, the test statistic is -3.0006.
(d)
To draw:
The conclusion and interpret the decision.

Answer to Problem 8E
Solution:
The null hypothesis is rejected and it is concluded that there is sufficient evidence at the 0.01 level of significance to support the claim that the mean number of customers is not lower on days following no advertisements than the mean number of customers on days following advertisements
Explanation of Solution
Given:
A new small business wants to know if its current radio advertising is effective. The owners decide to look at the mean number of customers who make a purchase in the store on days immediately following days when the radio ads are played as compared to the mean for those days following days when no radio advertisements are played. They found that for 11 days following no advertisements, the mean was 17.8 purchasing customers with a standard deviation of 3.5 customers. On 6 days following advertising, the mean was 22.8 purchasing customers with a standard deviation of 2.8 customers. Assume that the population variances are equal.
Calculation:
Rejection Regions for hypothesis tests for two population means reject the null hypothesis,
The alternative hypothesis contains “
It is given that
The calculated value of the test statistic is -3.0006 less than the critical value; it does falls in the rejection region. The null hypothesis is rejected.
Thus, it is concluded that there is sufficient evidence at the 0.01 level of significance to support the claim the mean number of customers is not lower on days following no advertisements than the mean number of customers on days following advertisements
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Chapter 11 Solutions
Beginning Statistics, 2nd Edition
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