a. For the equation a x 2 + b x + c = 0 ( a ≠ 0 ) , the formula gives the solutions as x = _______________. b. To apply the quadratic formula, a quadratic equation must be written in the form where ______________ a ≠ 0 . c. To apply the quadratic formula to solve the equation 8 x 2 − 42 x − 27 = 0 , the value of a is _____________, the value of b is _____________, and the value of c is __________. d. To apply the quadratic formula to solve the equation 3 x 2 − 7 x − 4 = 0 , the value of −-b is _____________ and the value of the radicand is _______________. e. The radicand within the quadratic formula is _________ and is called the ___________. f. If the discriminant is negative, then the solutions to a quadratic equation will be (real/imaginary) numbers. g. If the discriminant is positive, then the solutions to a quadratic equation will be (real/imaginary) numbers. h. Given a quadratic function f ( x ) = a x 2 + b x + c = 0 , the function will have no x -intercepts if the discriminant is (less than, greater than, equal to) zero.
a. For the equation a x 2 + b x + c = 0 ( a ≠ 0 ) , the formula gives the solutions as x = _______________. b. To apply the quadratic formula, a quadratic equation must be written in the form where ______________ a ≠ 0 . c. To apply the quadratic formula to solve the equation 8 x 2 − 42 x − 27 = 0 , the value of a is _____________, the value of b is _____________, and the value of c is __________. d. To apply the quadratic formula to solve the equation 3 x 2 − 7 x − 4 = 0 , the value of −-b is _____________ and the value of the radicand is _______________. e. The radicand within the quadratic formula is _________ and is called the ___________. f. If the discriminant is negative, then the solutions to a quadratic equation will be (real/imaginary) numbers. g. If the discriminant is positive, then the solutions to a quadratic equation will be (real/imaginary) numbers. h. Given a quadratic function f ( x ) = a x 2 + b x + c = 0 , the function will have no x -intercepts if the discriminant is (less than, greater than, equal to) zero.
Solution Summary: The author explains the quadratic formula for the equation ax2+bx+c=0.
a. For the equation
a
x
2
+
b
x
+
c
=
0
(
a
≠
0
)
, the formula gives the solutions as
x
=
_______________.
b. To apply the quadratic formula, a quadratic equation must be written in the form where ______________
a
≠
0
.
c. To apply the quadratic formula to solve the equation
8
x
2
−
42
x
−
27
=
0
, the value of a is _____________, the value of b is _____________, and the value of c is __________.
d. To apply the quadratic formula to solve the equation
3
x
2
−
7
x
−
4
=
0
, the value of −-b is _____________ and the value of the radicand is _______________.
e. The radicand within the quadratic formula is _________ and is called the ___________.
f. If the discriminant is negative, then the solutions to a quadratic equation will be (real/imaginary) numbers.
g. If the discriminant is positive, then the solutions to a quadratic equation will be (real/imaginary) numbers.
h. Given a quadratic function
f
(
x
)
=
a
x
2
+
b
x
+
c
=
0
, the function will have no x-intercepts if the discriminant is (less than, greater than, equal to) zero.
Formula Formula A polynomial with degree 2 is called a quadratic polynomial. A quadratic equation can be simplified to the standard form: ax² + bx + c = 0 Where, a ≠ 0. A, b, c are coefficients. c is also called "constant". 'x' is the unknown quantity
14
14
4. The graph shows the printing rate of Printer A. Printer B can
print at a rate of 25 pages per minute. How does the printing
rate for Printer B compare to the printing rate for Printer A?
The printing rate for Printer B is
than the rate
for Printer A because the rate of 25 pages per minute
is
than the rate of
for Printer A.
pages per minute
RIJOUT
40
fy
Printer Rat
Number of Pages
8N WA
10
30
20
Printer A
0
0
246
Time (min)
X
OR
16 f(x) =
Ef 16
χ
по
x²-2 410 | y = (x+2) + 4
Y-INT: y = 0
X-INT: X=0
VA: x=2
OA: y=x+2
0
X-INT: X=-2
X-INT: y = 2
VA
0
2
whole.
2-2
4
y - (x+2) = 27-270
+
xxx> 2
क्
above OA
(x+2) OA
x-2/x²+0x+0
2
x-2x
2x+O
2x-4
4
X<-1000 4/4/2<0 below Of
y
VA
X=2
X-2
OA
y=x+2
-2
2
(0,0)
2
χ
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