FUND MAT SCI+ENG ACCESS+EPUB
FUND MAT SCI+ENG ACCESS+EPUB
5th Edition
ISBN: 9781119662815
Author: Callister
Publisher: WILEY
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Chapter 11.17, Problem 6DP
To determine

Whether it is possible to produce an iron-carbon alloy with a minimum hardness of 200HB and a minimum ductility of 35%RA ? Give its composition and microstructure.

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8. The thermal decomposition of nitric oxide at elevated temperatures 2NO → N₂+02 has been studied in a batch reactor where at temperatures below 2000K the rate expression that applies to low conversions is: r = kCm05 Co At high conversions, or when the initial mixture contains a high concentration of O2 the rate expression is given by: r = k' Cм0.5 C15C0,5 To explain these kinetics the following chain reaction mechanism has been proposed: Initiation: Propagation: 2NON₂O +0 k₂ E1=272.0 kJ/mol 0+ NO O₂+ N E₂-161.0 kJ/mol N+NO N₂+0 E3-1.4 kJ/mol K4 20+ MO₂+M E4=14.0 kJ/mol ks Termination: where M is any molecule capable of the energy transfer necessary to stabilize the oxygen molecule. Once appreciable amounts of O2 are present in the reaction mixture, the initiation reaction that is the primary source of atomic oxygen is no longer the first reaction. Instead, the following reaction begins to dominate the chain initiation process: Initiation (high O2): ks NO +0₂ NO₂+0 E5=198.0 kJ/mol a.…
Calculate the current magnitude in the coils e1, e2 of theMagnetic circuit, if:ɸa = 3.00 x 10^-3 Wb, φb = 0.80 x 10^-3 Wb, ɸc = 2.20 x 10^-3 Wb L ab = 0.10 m,A ab = 5.0 cm^2L afeb = L acdb = 0.40 mA afeb = A acdb = 20 cm^2 MATERIAL CHARACTERISTICSH (At/m) 240  350  530  1300  5000  9000B (T)       0.7   0.9   1.1    1.3     1.5     1.6
A toroid magnetic circuit is composed of three sections A, B and C, thesection C has an air gap, section A has an 850 round coil thatconsumes a current of 1.2 A. the physical and magnetic properties of each sectionare: Section A: Length = 80 mm, Cross section = 120 mm^2, μr = 400 Section B: Length = 60 mm, Cross section = 40 mm^2, μr = 250 Section C: Length = 50 mm, Cross section = 200 mm^2, μr = 600 Gap: Length = 1 mm, Cross section = 40 mm^2, μr = 1 Calculate:The magnetic field density in each of the sections
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