Introduction to the Practice of Statistics
9th Edition
ISBN: 9781319013387
Author: David S. Moore, George P. McCabe, Bruce A. Craig
Publisher: W. H. Freeman
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Chapter 11.1, Problem 8E
(a)
To determine
The
(b)
To determine
The degrees of freedom of the test.
(c)
To determine
The P- values for the test.
(d)
To determine
The proportion of variation in the response variable as explained by the explanatory variable.
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Students have asked these similar questions
8. Recall, from Sect. 2.16.4, the likelihood ratio statistic, Ln, which was defined
as a product of independent, identically distributed random variables with mean
1 (under the so-called null hypothesis), and the, sometimes more convenient,
log-likelihood, log L, which was a sum of independent, identically distributed
random variables, which, however, do not have mean log 1 = 0.
(a) Verify that the last claim is correct, by proving the more general statement,
namely that, if Y is a non-negative random variable with finite mean, then
E(log Y) log(EY).
(b) Prove that, in fact, there is strict inequality:
E(log Y) < log(EY),
unless Y is degenerate.
(c) Review the proof of Jensen's inequality, Theorem 5.1. Generalize with a
glimpse on (b).
3. Prove that, for any random variable X, the minimum of E(X - a)² is attained
for a = EX.
Proved
7. Cantelli's inequality. Let X be a random variable with finite variance, o².
(a) Prove that, for x ≥ 0,
P(X EX2x)≤
02
x² +0²
202
P(|X - EX2x)<≤
(b) Find X assuming two values where there is equality.
(c) When is Cantelli's inequality better than Chebyshev's inequality?
(d) Use Cantelli's inequality to show that med (X) - EX ≤ o√√3; recall,
from Proposition 6.1, that an application of Chebyshev's inequality yields
the bound o√√2.
(e) Generalize Cantelli's inequality to moments of order r 1.
Chapter 11 Solutions
Introduction to the Practice of Statistics
Ch. 11.1 - Prob. 1UYKCh. 11.1 - Prob. 2UYKCh. 11.1 - Prob. 3ECh. 11.1 - Prob. 4ECh. 11.1 - Prob. 5ECh. 11.1 - Prob. 6ECh. 11.1 - Prob. 7ECh. 11.1 - Prob. 8ECh. 11.1 - Prob. 9ECh. 11.1 - Prob. 10E
Ch. 11.1 - Prob. 11ECh. 11.1 - Prob. 12ECh. 11.2 - Prob. 13UYKCh. 11.2 - Prob. 14UYKCh. 11.2 - Prob. 15ECh. 11.2 - Prob. 16ECh. 11.2 - Prob. 17ECh. 11.2 - Prob. 18ECh. 11.2 - Prob. 19ECh. 11.2 - Prob. 20ECh. 11.2 - Prob. 21ECh. 11.2 - Prob. 22ECh. 11.2 - Prob. 23ECh. 11.2 - Prob. 24ECh. 11 - Prob. 25ECh. 11 - Prob. 26ECh. 11 - Prob. 27ECh. 11 - Prob. 28ECh. 11 - Prob. 29ECh. 11 - Prob. 30ECh. 11 - Prob. 31ECh. 11 - Prob. 32ECh. 11 - Prob. 33ECh. 11 - Prob. 34ECh. 11 - Prob. 35ECh. 11 - Prob. 36ECh. 11 - Prob. 37ECh. 11 - Prob. 38ECh. 11 - Prob. 39ECh. 11 - Prob. 40ECh. 11 - Prob. 41ECh. 11 - Prob. 42ECh. 11 - Prob. 43ECh. 11 - Prob. 44ECh. 11 - Prob. 45ECh. 11 - Prob. 46ECh. 11 - Prob. 47ECh. 11 - Prob. 48ECh. 11 - Prob. 49ECh. 11 - Prob. 50ECh. 11 - Prob. 51ECh. 11 - Prob. 52ECh. 11 - Prob. 53ECh. 11 - Prob. 54ECh. 11 - Prob. 55ECh. 11 - Prob. 56ECh. 11 - Prob. 57ECh. 11 - Prob. 58ECh. 11 - Prob. 59ECh. 11 - Prob. 60ECh. 11 - Prob. 61ECh. 11 - Prob. 62ECh. 11 - Prob. 63ECh. 11 - Prob. 64ECh. 11 - Prob. 65ECh. 11 - Prob. 66E
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