Explanation Given Information: The provided function is y = log 2 ( 1 − x − x 2 ) . Formula Used: The change of base formula is such that, for log b M = log a M log a b , where a , b are the base of logarithm and M is any positive number. Coefficient rule for a constant c is such that, if f ( x ) = c ⋅ u ( x ) , where u ( x ) is a differentiable function of x , then f ′ ( x ) = c ⋅ u ′ ( x ) . Derivative of natural logarithmic functions is such that, if y = ln u , where u is a differentiable function of x then d y d x = 1 u ⋅ d u d x . Calculation: Consider the function, y = log 2 ( 1 − x − x 2 ) Use the change of base property of logarithms, y = ln ( 1 − x − x 2 ) ln 2 Differentiate with respect to x , d y d x = d d x [ ln ( 1 − <

MATHMATICAL APPLICATIONS FOR THE MANAGEM

11th Edition

ISBN: 9781305758063

Author: HARSHBARGER

Publisher: CENGAGE C

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Differential Equations

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Chapter 11.1, Problem 38E

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To calculate: The value of y′ for the function y=log2(1−x−x2).

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Chapter 11.1, Problem 37E

Chapter 11.1, Problem 39E

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Chapter 11 Solutions

MATHMATICAL APPLICATIONS FOR THE MANAGEM

Ch. 11.1 - 1. Ch. 11.1 - 2. If Ch. 11.1 - Prob. 3CP Ch. 11.1 - 4. Find . Ch. 11.1 - Prob. 1E Ch. 11.1 - Prob. 2E Ch. 11.1 - Prob. 3E Ch. 11.1 - Prob. 4E Ch. 11.1 - Prob. 5E Ch. 11.1 - Find the derivatives of the functions in Problems...

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The value of y ′ for the function y = log 2 ( 1 − x − x 2 ) .

Solution Summary: The author analyzes the function y=mathrmlog_2(1-x-x 2).

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To calculate: The value of y′ for the function y=log2(1−x−x2).

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Chapter 11 Solutions