(a) Explanation “The equation of the parabola with vertex V ( 0 , 0 ) , focus F ( 0 , p ) and directrix y = − p is x 2 = 4 p y .” “The length of the focal diameter of the parabola x 2 = 4 p y is | 4 p | .” Calculation: The equation 8 x 2 + 12 y = 0 can be written as follows, 8 x 2 = − 12 y x 2 = − 4 3 y . Now compare the above equation x 2 = − 4 3 y (b) To determine To sketch: The graph of the parabola x 2 + 12 y = 0 and its directrix.

7th Edition

ISBN: 9781305718906

Author: Stewart

Publisher: CENGAGE L

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Chapter 11.1, Problem 24E

(a)

To determine

To Find: The focus, directrix and focal diameter of the parabola 8x2+12y=0 .

(b)

To determine

To sketch: The graph of the parabola x2+12y=0 and its directrix.

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Chapter 11.1, Problem 23E

Chapter 11.1, Problem 25E

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Chapter 11 Solutions

PRECALCULUS: MATHEMATICS FOR CALCULUS

Ch. 11.1 - A parabola is the set of all points in the plane...Ch. 11.1 - The graph of the equation x2 = 4py is a parabola...Ch. 11.1 - The graph of the equation y2 = 4px is a parabola...Ch. 11.1 - Label the focus, directrix, and vertex on the...Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Prob. 6E Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Prob. 8E Ch. 11.1 - Graphs of Parabolas Match the equation with the...Ch. 11.1 - Graphs of Parabolas Match the equation with the...

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The focus, directrix and focal diameter of the parabola 8 x 2 + 12 y = 0 .

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