Chapter 11.1, Problem 15E

a.

To determine

To find: the interval with greatest frequency.

Answer to Problem 15E

The interval with greatest frequency is $\text{25-29}$ .

Explanation of Solution

Given information: from the figure provided in the question it is observed that,

  $\begin{array}{l}\text{10-14=7}\\ \text{15-19=3}\\ \text{20-24=6}\\ \text{25-29=9}\\ \text{30-34=5}\end{array}$

Calculation: For find the interval with the greatest frequency observe the highest height histogram,

In this histogram the interval $\text{25-29}$ has the highest height. So it is the interval with the greatest frequency.

b.

To determine

To find: the percent of the peoples who take fewer than 20 vacation days.

Answer to Problem 15E

The percent of the peoples who take fewer than 20 vacation days is $\text{3\%}$ .

Explanation of Solution

The percent of the peoples who take fewer than 20 vacation days is $\text{3\%}$ .

Given information: from the figure provided in the question it is observed that,

  $\begin{array}{l}\text{10-14=7}\\ \text{15-19=3}\\ \text{20-24=6}\\ \text{25-29=9}\\ \text{30-34=5}\end{array}$

Calculation: To find the percent we observe first the fewer than 20 vacation days per year frequency then get the percent with the total,

  $\begin{array}{l}\text{3 out of 10}\\ \frac{3·100}{10}=3\%\end{array}$

c.

To determine

To compare: the shanghai data with north America and Europe data.

Answer to Problem 15E

Shanghai average vacation is less than north America and Europe vacations.

Explanation of Solution

Shanghai average vacation is less than north America and Europe vacations.

Given information: shanghai average vacations is 16 days per year.

from the given figure it can be observed that the average vacations per year is greater than shanghai average vacations.