MyLab Statistics with Pearson eText -- Standalone Access Card -- for Biostatistics for the Biological and Health Sciences (My Stat Lab)
2nd Edition
ISBN: 9780134748870
Author: Marc M. Triola, Mario F. Triola, Jason Roy
Publisher: PEARSON
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Chapter 1.1, Problem 8SLCT
To determine
To explain whether the given source has the potential to create bias in a statistical study.
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Microsoft Excel snapshot for random sampling: Also note the formula used for the last
column
02
x✓ fx =INDEX(5852:58551, RANK(C2, $C$2:$C$51))
A
B
1
No.
States
2
1
ALABAMA
Rand No.
0.925957526
3
2
ALASKA
0.372999976
4
3
ARIZONA
0.941323044
5
4 ARKANSAS
0.071266381
Random Sample
CALIFORNIA
NORTH CAROLINA
ARKANSAS
WASHINGTON
G7
Microsoft Excel snapshot for systematic sampling:
xfx INDEX(SD52:50551, F7)
A
B
E
F
G
1
No.
States
Rand No. Random Sample
population
50
2
1 ALABAMA
0.5296685 NEW HAMPSHIRE
sample
10
3
2 ALASKA
0.4493186 OKLAHOMA
k
5
4
3 ARIZONA
0.707914 KANSAS
5
4 ARKANSAS 0.4831379 NORTH DAKOTA
6
5 CALIFORNIA 0.7277162 INDIANA
Random Sample
Sample Name
7
6 COLORADO 0.5865002 MISSISSIPPI
8
7:ONNECTICU 0.7640596 ILLINOIS
9
8 DELAWARE 0.5783029 MISSOURI
525
10
15
INDIANA
MARYLAND
COLORADO
Suppose the Internal Revenue Service reported that the mean tax refund for the year 2022 was $3401. Assume the standard deviation is $82.5 and that the amounts refunded follow a normal probability distribution. Solve the following three parts? (For the answer to question 14, 15, and 16, start with making a bell curve. Identify on the bell curve where is mean, X, and area(s) to be determined.
1.What percent of the refunds are more than $3,500?
2. What percent of the refunds are more than $3500 but less than $3579?
3. What percent of the refunds are more than $3325 but less than $3579?
A normal distribution has a mean of 50 and a standard deviation of 4. Solve the following three parts?
1. Compute the probability of a value between 44.0 and 55.0.
(The question requires finding probability value between 44 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 44, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the answer of the second part.)
2. Compute the probability of a value greater than 55.0.
Use the same formula, x=55 and subtract the answer from 1.
3. Compute the probability of a value between 52.0 and 55.0.
(The question requires finding probability value between 52 and 55. Solve it in 3 steps.
In the first step, use the above formula and x = 52, calculate probability value.
In the second step repeat the first step with the only difference that x=55.
In the third step, subtract the answer of the first part from the…
Chapter 1 Solutions
MyLab Statistics with Pearson eText -- Standalone Access Card -- for Biostatistics for the Biological and Health Sciences (My Stat Lab)
Ch. 1.1 - Prob. 1SLCTCh. 1.1 - Prob. 2SLCTCh. 1.1 - Prob. 3SLCTCh. 1.1 - Prob. 4SLCTCh. 1.1 - Prob. 5SLCTCh. 1.1 - Prob. 6SLCTCh. 1.1 - Prob. 7SLCTCh. 1.1 - Prob. 8SLCTCh. 1.1 - Prob. 9SLCTCh. 1.1 - Prob. 10SLCT
Ch. 1.1 - Prob. 11SLCTCh. 1.1 - Prob. 12SLCTCh. 1.1 - Prob. 13SLCTCh. 1.1 - Prob. 14SLCTCh. 1.1 - Prob. 15SLCTCh. 1.1 - Prob. 16SLCTCh. 1.1 - Prob. 17SLCTCh. 1.1 - Prob. 18SLCTCh. 1.1 - Prob. 19SLCTCh. 1.1 - Prob. 20SLCTCh. 1.1 - Prob. 21SLCTCh. 1.1 - Prob. 22SLCTCh. 1.1 - Prob. 23SLCTCh. 1.1 - Prob. 24SLCTCh. 1.1 - Prob. 25SLCTCh. 1.1 - Prob. 26SLCTCh. 1.1 - Prob. 27SLCTCh. 1.1 - Prob. 28SLCTCh. 1.1 - Prob. 29SLCTCh. 1.1 - Prob. 30SLCTCh. 1.1 - Prob. 31SLCTCh. 1.1 - Prob. 32SLCTCh. 1.2 - Prob. 1SLCTCh. 1.2 - Prob. 2SLCTCh. 1.2 - Prob. 3SLCTCh. 1.2 - Prob. 4SLCTCh. 1.2 - Prob. 5SLCTCh. 1.2 - Prob. 6SLCTCh. 1.2 - Prob. 7SLCTCh. 1.2 - Prob. 8SLCTCh. 1.2 - Prob. 9SLCTCh. 1.2 - Prob. 10SLCTCh. 1.2 - Prob. 11SLCTCh. 1.2 - Prob. 12SLCTCh. 1.2 - Prob. 13SLCTCh. 1.2 - Prob. 14SLCTCh. 1.2 - Prob. 15SLCTCh. 1.2 - Prob. 16SLCTCh. 1.2 - Prob. 17SLCTCh. 1.2 - Prob. 18SLCTCh. 1.2 - Prob. 19SLCTCh. 1.2 - Prob. 20SLCTCh. 1.2 - Prob. 21SLCTCh. 1.2 - Prob. 22SLCTCh. 1.2 - Prob. 23SLCTCh. 1.2 - Prob. 24SLCTCh. 1.2 - Prob. 25SLCTCh. 1.2 - Prob. 26SLCTCh. 1.2 - Prob. 27SLCTCh. 1.2 - Prob. 28SLCTCh. 1.2 - Prob. 29SLCTCh. 1.2 - Prob. 30SLCTCh. 1.2 - Prob. 31SLCTCh. 1.2 - Prob. 32SLCTCh. 1.2 - Prob. 33SLCTCh. 1.3 - Prob. 1SLCTCh. 1.3 - Prob. 2SLCTCh. 1.3 - Prob. 3SLCTCh. 1.3 - Prob. 4SLCTCh. 1.3 - Prob. 5SLCTCh. 1.3 - Prob. 6SLCTCh. 1.3 - Prob. 7SLCTCh. 1.3 - Prob. 8SLCTCh. 1.3 - Prob. 9SLCTCh. 1.3 - Prob. 10SLCTCh. 1.3 - Prob. 11SLCTCh. 1.3 - Prob. 12SLCTCh. 1.3 - Prob. 13SLCTCh. 1.3 - Prob. 14SLCTCh. 1.3 - Prob. 15SLCTCh. 1.3 - Prob. 16SLCTCh. 1.3 - Prob. 17SLCTCh. 1.3 - Prob. 18SLCTCh. 1.3 - Prob. 19SLCTCh. 1.3 - Prob. 20SLCTCh. 1.3 - Prob. 21SLCTCh. 1.3 - Prob. 22SLCTCh. 1.3 - Prob. 23SLCTCh. 1.3 - Prob. 24SLCTCh. 1.3 - Prob. 25SLCTCh. 1.3 - Prob. 26SLCTCh. 1.3 - Prob. 27SLCTCh. 1.3 - Prob. 28SLCTCh. 1.3 - Prob. 29SLCTCh. 1.3 - Prob. 30SLCTCh. 1.3 - Prob. 31SLCTCh. 1.3 - Prob. 32SLCTCh. 1.3 - Prob. 33SLCTCh. 1.3 - Prob. 34SLCTCh. 1.3 - Prob. 35SLCTCh. 1.3 - Prob. 36SLCTCh. 1.3 - Prob. 37SLCTCh. 1.3 - Prob. 38SLCTCh. 1 - Prob. 1CQQCh. 1 - Prob. 2CQQCh. 1 - Prob. 3CQQCh. 1 - Prob. 4CQQCh. 1 - Prob. 5CQQCh. 1 - Prob. 6CQQCh. 1 - Prob. 7CQQCh. 1 - Prob. 8CQQCh. 1 - Prob. 9CQQCh. 1 - Prob. 10CQQCh. 1 - Prob. 1RECh. 1 - Prob. 2RECh. 1 - Prob. 3RECh. 1 - Prob. 4RECh. 1 - Prob. 5RECh. 1 - Prob. 6RECh. 1 - Prob. 7RECh. 1 - Prob. 8RECh. 1 - Prob. 9RECh. 1 - Prob. 10RECh. 1 - Prob. 1CRECh. 1 - Prob. 2CRECh. 1 - Prob. 3CRECh. 1 - Prob. 4CRECh. 1 - Prob. 5CRECh. 1 - Prob. 6CRECh. 1 - Prob. 7CRECh. 1 - Prob. 8CRECh. 1 - Prob. 9CRECh. 1 - Prob. 10CRECh. 1 - Prob. 11CRECh. 1 - Prob. 12CRE
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