Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
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Textbook Question
Chapter 11, Problem 8P
The v = 0 to v = 1 vibrational transition of the HI molecule occurs at a frequency of 6.69 × 1013 Hz. The same transition for the NO molecule occurs at a frequency of 5.63 × 1013 Hz. Calculate (a) the effective force constant and (b) the amplitude of vibration for each molecule. (c) Explain why the force constant of the NO molecule is so much larger than that of the HI molecule.
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Example
Two charges, one with +10 μC of charge, and
another with - 7.0 μC of charge are placed in
line with each other and held at a fixed distance
of 0.45 m. Where can you put a 3rd charge of +5
μC, so that the net force on the 3rd charge is
zero?
*
Coulomb's Law Example
Three charges are positioned as seen below. Charge
1 is +2.0 μC and charge 2 is +8.0μC, and charge 3 is -
6.0MC.
What is the magnitude and the direction of the force
on charge 2 due to charges 1 and 3?
93
kq92
F
==
2
r13 = 0.090m
91
r12 = 0.12m
92
Coulomb's Constant: k = 8.99x10+9 Nm²/C²
✓
Make sure to draw a Free Body Diagram as well
Chapter 11 Solutions
Modern Physics
Ch. 11.2 - Compare the effective force constant for the CO...Ch. 11 - Prob. 1QCh. 11 - Prob. 2QCh. 11 - Prob. 3QCh. 11 - Prob. 4QCh. 11 - Prob. 5QCh. 11 - Prob. 7QCh. 11 - Prob. 8QCh. 11 - Prob. 9QCh. 11 - Prob. 1P
Ch. 11 - Use the data in Table 11.2 to calculate the...Ch. 11 - The CO molecule undergoes a rotational transition...Ch. 11 - Prob. 4PCh. 11 - Prob. 5PCh. 11 - Prob. 6PCh. 11 - Prob. 7PCh. 11 - The v = 0 to v = 1 vibrational transition of the...Ch. 11 - Consider the HCl molecule, which consists of a...Ch. 11 - Prob. 10PCh. 11 - Prob. 11PCh. 11 - Prob. 12PCh. 11 - Prob. 13PCh. 11 - Prob. 14PCh. 11 - Prob. 15PCh. 11 - Prob. 18P
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