COLLEGE PHYSICS,VOLUME 1
COLLEGE PHYSICS,VOLUME 1
2nd Edition
ISBN: 9781319115104
Author: Freedman
Publisher: MAC HIGHER
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Chapter 11, Problem 84QAP
To determine

(a)

Height of the cube of gold won in lottery and is it possible for the person to take it to home?

Expert Solution
Check Mark

Answer to Problem 84QAP

The height is 71.017 cm and yes, it is possible to take it at home.

Explanation of Solution

Given:

Price of lottery  = 146.9 million euros = 211.8 million U.S. Dollars

Rate of gold  = $953 per try ounce

Rate of silver  = $14.16 per troy ounce

Relation= 31.1035 g

Density of gold  = 19.3 g/cm3

Density of silver  = 10.5g/cm3

Formula used:

  Density(d) = mass(m)Volume(V)Volume of cube = (side)3

Calculation:

Substituting the values,

  Density(d) = mass(m)Volume(V)Volume of cube = (side)3

  $211.8×106 = $2.118×1081 Troy ounce = $953Number of troy ouncesN = 2.118× 108953N = 222245.5404 try ounces1 Troy ounce = 31.1035 g222245.5404 try ounces =222245.5404× 31.1035 gTherefore mass = 6912614.166 gDensity(d) = mass(m)Volume(V)Volume(V) = mass(m)Density(d)Volume(V) = 6912614.166 g19 .3 g/cm3Volume(V) = 358166.5372 cm3Now,Volume of cube = (side)3side = 358166.5372  cm33side = 71.017 cm

Conclusion:

The flow rate is 0.11×103 m3/s

To determine

(b)

Calculate the height of the silver cube with the same lottery amount.

Expert Solution
Check Mark

Answer to Problem 84QAP

The height of the silver cube will be 353.856 cm

Explanation of Solution

Given:

Price of lottery  = 146.9 million euros = 211.8 million U.S. Dollars

Rate of gold  = $953 per try ounce

Rate of silver  = $14.16 per troy ounce

Relation= 31.1035 g

Density of gold  = 19.3 g/cm3

Density of silver  = 10.5g/cm3

Formula used:

  Density(d) = mass(m)Volume(V)Volume of cube = (side)3

Calculation:

Substituting the values,

  Density(d) = mass(m)Volume(V)Volume of cube = (side)3

  $211.8×106 = $2.118×1081 Troy ounce = $14.16Number of troy ouncesN = 2.118× 10814.16N = 14957627.1186 try ounces1 Troy ounce = 31.1035 g14957627.1186 try ounces =14957627.1186× 31.1035 gTherefore mass = 465234555.0833 gDensity(d) = mass(m)Volume(V)Volume(V) = mass(m)Density(d)Volume(V) = 465234555.0833 g10 .5 g/cm3Volume(V) = 44308052.8650 cm3Now,Volume of cube = (side)3side = 44308052 .8650 cm33side = 353.856 cm

Conclusion:

Thus, the height of the silver cube will be 353.856 cm

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Chapter 11 Solutions

COLLEGE PHYSICS,VOLUME 1

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