a. Repeat the following procedure with at least five people. Write a conjecture that relates the result of the procedure to each person’s birthday. Take the number of the month of your birthday ( January = 1 , February = 2 , ... , December = 12 ) , multiply by 5, add 6, multiply this sum by 4, add 9, multiply this new sum by 5, and add the number of the day on which you were born. Finally, subtract 165. b. Let M represent the month number and let D represent the day number of any person’s birthday. Use deductive reasoning to prove your conjecture in part (a).
a. Repeat the following procedure with at least five people. Write a conjecture that relates the result of the procedure to each person’s birthday. Take the number of the month of your birthday ( January = 1 , February = 2 , ... , December = 12 ) , multiply by 5, add 6, multiply this sum by 4, add 9, multiply this new sum by 5, and add the number of the day on which you were born. Finally, subtract 165. b. Let M represent the month number and let D represent the day number of any person’s birthday. Use deductive reasoning to prove your conjecture in part (a).
Solution Summary: The author explains how to calculate a conjecture that relates to the process described in the question below.
a. Repeat the following procedure with at least five people. Write a conjecture that relates the result of the procedure to each person’s birthday.
Take the number of the month of your birthday
(
January
=
1
,
February
=
2
,
...
,
December
=
12
)
, multiply by 5, add 6, multiply this sum by 4, add 9, multiply this new sum by 5, and add the number of the day on which you were born. Finally, subtract 165.
b. Let M represent the month number and let D represent the day number of any person’s birthday. Use deductive reasoning to prove your conjecture in part (a).
By considering appropriate series expansions,
e². e²²/2. e²³/3.
....
=
= 1 + x + x² + ·
...
when |x| < 1.
By expanding each individual exponential term on the left-hand side
the coefficient of x- 19 has the form
and multiplying out,
1/19!1/19+r/s,
where 19 does not divide s. Deduce that
18! 1 (mod 19).
Proof: LN⎯⎯⎯⎯⎯LN¯ divides quadrilateral KLMN into two triangles. The sum of the angle measures in each triangle is ˚, so the sum of the angle measures for both triangles is ˚. So, m∠K+m∠L+m∠M+m∠N=m∠K+m∠L+m∠M+m∠N=˚. Because ∠K≅∠M∠K≅∠M and ∠N≅∠L, m∠K=m∠M∠N≅∠L, m∠K=m∠M and m∠N=m∠Lm∠N=m∠L by the definition of congruence. By the Substitution Property of Equality, m∠K+m∠L+m∠K+m∠L=m∠K+m∠L+m∠K+m∠L=°,°, so (m∠K)+ m∠K+ (m∠L)= m∠L= ˚. Dividing each side by gives m∠K+m∠L=m∠K+m∠L= °.°. The consecutive angles are supplementary, so KN⎯⎯⎯⎯⎯⎯∥LM⎯⎯⎯⎯⎯⎯KN¯∥LM¯ by the Converse of the Consecutive Interior Angles Theorem. Likewise, (m∠K)+m∠K+ (m∠N)=m∠N= ˚, or m∠K+m∠N=m∠K+m∠N= ˚. So these consecutive angles are supplementary and KL⎯⎯⎯⎯⎯∥NM⎯⎯⎯⎯⎯⎯KL¯∥NM¯ by the Converse of the Consecutive Interior Angles Theorem. Opposite sides are parallel, so quadrilateral KLMN is a parallelogram.
By considering appropriate series expansions,
ex · ex²/2 . ¸²³/³ . . ..
=
= 1 + x + x² +……
when |x| < 1.
By expanding each individual exponential term on the left-hand side
and multiplying out, show that the coefficient of x 19 has the form
1/19!+1/19+r/s,
where 19 does not divide s.
Chapter 1 Solutions
Thinking Mathematically plus NEW MyLab Math with Pearson eText -- Access Card Package (6th Edition)
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