The Carnot efficiency.

Question

Want to see more full solutions like this?

Answer 1

Question

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Students have asked these similar questions

For each of the actions depicted below, a magnet and/or metal loop moves with velocity v→ (v→ is constant and has the same magnitude in all parts). Determine whether a current is induced in the metal loop. If so, indicate the direction of the current in the loop, either clockwise or counterclockwise when seen from the right of the loop. The axis of the magnet is lined up with the center of the loop. For the action depicted in (Figure 5), indicate the direction of the induced current in the loop (clockwise, counterclockwise or zero, when seen from the right of the loop). I know that the current is clockwise, I just dont understand why. Please fully explain why it's clockwise, Thank you

A planar double pendulum consists of two point masses \[m_1 = 1.00~\mathrm{kg}, \qquad m_2 = 1.00~\mathrm{kg}\]connected by massless, rigid rods of lengths \[L_1 = 1.00~\mathrm{m}, \qquad L_2 = 1.20~\mathrm{m}.\]The upper rod is hinged to a fixed pivot; gravity acts vertically downward with\[g = 9.81~\mathrm{m\,s^{-2}}.\]Define the generalized coordinates \(\theta_1,\theta_2\) as the angles each rod makes with thedownward vertical (positive anticlockwise, measured in radians unless stated otherwise).At \(t=0\) the system is released from rest with \[\theta_1(0)=120^{\circ}, \qquad\theta_2(0)=-10^{\circ}, \qquad\dot{\theta}_1(0)=\dot{\theta}_2(0)=0 .\]Using the exact nonlinear equations of motion (no small-angle or planar-pendulumapproximations) and assuming the rods never stretch or slip, determine the angle\(\theta_2\) at the instant\[t = 10.0~\mathrm{s}.\]Give the result in degrees, in the interval \((-180^{\circ},180^{\circ}]\).

What are the expected readings of the ammeter and voltmeter for the circuit in the figure below? (R = 5.60 Ω, ΔV = 6.30 V) ammeter I =

Answer 2

Question

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 3

Question

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 4

Question

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

Answer 5

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Answer 6

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

Answer 7

Chapter 11, Problem 5SP

(a)

To determine

The Carnot efficiency.

Answer 8

(a)

Expert Solution

Answer to Problem 5SP

The Carnot efficiency is 44.4 %.

Answer 9

(a)

Expert Solution

Answer 10

(a)

Expert Solution

Answer 11

Expert Solution

Answer 12

Explanation of Solution

Given info: The temperature range of the turbine is 240°C to 650°C and the efficiency is 80%.

Write an expression to calculate the efficiency.

η=1−TCTH

Here,

η is the efficiency of the Carnot engine

TC is the temperature of cold reservoir

TH is the temperature of hot reservoir

Substitute 240 °C for TC and 650°C for TH to find η.

η=1−(240+273) K(650 +273) K=0.444=(0.444)(100 %)=44.4%

Thus, the Carnot efficiency is 44.4 %.

Conclusion:

The Carnot efficiency is 44.4 %.

Answer 13

(b)

To determine

The efficiency of the actual oil-fired turbines.

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

Answer 14

(b)

To determine

The efficiency of the actual oil-fired turbines.

Answer 15

(b)

Expert Solution

Answer to Problem 5SP

The efficiency of the actual oil-fired turbines is 35.52 %.

Answer 16

(b)

Expert Solution

Answer 17

(b)

Expert Solution

Answer 18

Expert Solution

Answer 19

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

η'=80% η

Here,

η' is the efficiency of the oil-fired power plant.

Substitute 0.444 for η to find η'.

W=(80 %)(0.444)=35.52 %

Thus, the efficiency of the actual oil-fired turbines is 35.52 %.

Conclusion:

Therefore, the efficiency of the actual oil-fired turbines is 35.52 %.

Answer 20

(c)

To determine

The electrical energy generated by the plant in one hour.

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Answer 21

(c)

To determine

The electrical energy generated by the plant in one hour.

Answer 22

(c)

Expert Solution

Answer to Problem 5SP

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Answer 23

(c)

Expert Solution

Answer 24

(c)

Expert Solution

Answer 25

Expert Solution

Answer 26

Explanation of Solution

Given info: The power of the oil-fired power plant is 100 MW and the time is 1 h.

Write an expression for electrical energy generated by the plant in one hour.

E=Pt

Here,

E is the energy

P is the energy

t is the energy

Substitute 100 MW for P and 1 h for t to find E.

E=(100 MW)(103 kW1 MW)(1 h)=1×105 kW⋅h

Thus, the electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Conclusion:

The electrical energy generated by the plant in one hour is 1×105 kW⋅h.

Answer 27

(d)

To determine

The heat obtained from oil in each hour.

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Answer 28

(d)

To determine

The heat obtained from oil in each hour.

Answer 29

(d)

Expert Solution

Answer to Problem 5SP

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Answer 30

(d)

Expert Solution

Answer 31

(d)

Expert Solution

Answer 32

Expert Solution

Answer 33

Explanation of Solution

Write an expression for efficiency of the actual oil-fired turbines.

E'=Eη'

Here,

E' is the heat obtained from oil in each hour.

Substitute 0.444 for η' and 1×105 kW⋅h for E to find η'.

E'=1×105 kW⋅h0.444=2.25×105 kW⋅h

Thus, the heat obtained from oil in each hour is 2.25×105 kW⋅h.

Conclusion:

The heat obtained from oil in each hour is 2.25×105 kW⋅h.

Answer 34

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Answer 35

(e)

To determine

The amount of oil required to produce 1,700 kW⋅h in each hour.

Answer 36

(e)

Expert Solution

Answer to Problem 5SP

The amount of oil required to produce 1,700 kW⋅h in each hour is 259 barrels of oil.

Answer 37

(e)

Expert Solution

Answer 38

(e)

Expert Solution

Answer 39

Expert Solution

Answer 40

Explanation of Solution

Write an expression for the amount of oil required to produce 1,700 kW⋅h in an hour.

n=E'Eh

Here,

E' is the energy released per hour

Eh is the energy released from one barrel oil per hour

n is the amount of oil required to produce 1700 kW⋅h in an hour

Substitute 2.25×105 kW⋅h for E' and 1700 kW⋅h for Eh to find n.

n=2.25×105 kW⋅h1,700 kW⋅h/barrel=132.5 barrels≈133 barrels

Thus, the amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil

Conclusion:

The amount of oil required to produce 1700 kW⋅h in each hour is 133 barrels of oil.

Answer 41

Ch. 11 - Prob. 1CQ Ch. 11 - Prob. 2CQ Ch. 11 - In applying the first law of thermodynamics to a...Ch. 11 - Is the total amount of heat released by a heat...Ch. 11 - From the perspective of the first law of...Ch. 11 - Which motor in a hybrid vehiclethe electric or...Ch. 11 - Prob. 7CQ Ch. 11 - Prob. 8CQ Ch. 11 - Prob. 9CQ Ch. 11 - Prob. 10CQ

The Carnot efficiency.

The Carnot efficiency.

Answer to Problem 5SP

Explanation of Solution

The efficiency of the actual oil-fired turbines.

Answer to Problem 5SP

Explanation of Solution

The electrical energy generated by the plant in one hour.

Answer to Problem 5SP

Explanation of Solution

The heat obtained from oil in each hour.

Answer to Problem 5SP

Explanation of Solution

The amount of oil required to produce 1,700 kW⋅h in each hour.

Answer to Problem 5SP

Explanation of Solution

Want to see more full solutions like this?

Chapter 11 Solutions