EBK DISCRETE MATHEMATICS: INTRODUCTION
11th Edition
ISBN: 9781133417071
Author: EPP
Publisher: CENGAGE LEARNING - CONSIGNMENT
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Chapter 1.1, Problem 5ES
a.
To determine
To calculate: The solutions of the blank using the variable.
b.
To determine
To calculate: The solutions of the blank using the variable.
c.
To determine
To calculate: The solutions of the blank using the variable.
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(b) Let I[y] be a functional of y(x) defined by
[[y] = √(x²y' + 2xyy' + 2xy + y²) dr,
subject to boundary conditions
y(0) = 0,
y(1) = 1.
State the Euler-Lagrange equation for finding extreme values of I [y] for this prob-
lem. Explain why the function y(x) = x is an extremal, and for this function,
show that I = 2. Without doing further calculations, give the values of I for the
functions y(x) = x² and y(x) = x³.
Please use mathematical induction to prove this
In simplest terms, Sketch the graph of the parabola. Then, determine its equation.
opens downward, vertex is (- 4, 7), passes through point (0, - 39)
Chapter 1 Solutions
EBK DISCRETE MATHEMATICS: INTRODUCTION
Ch. 1.1 - Prob. 1ESCh. 1.1 - Prob. 2ESCh. 1.1 - Prob. 3ESCh. 1.1 - Prob. 4ESCh. 1.1 - Prob. 5ESCh. 1.1 - Prob. 6ESCh. 1.1 - Prob. 7ESCh. 1.1 - Prob. 8ESCh. 1.1 - Prob. 9ESCh. 1.1 - Prob. 10ES
Ch. 1.1 - Prob. 11ESCh. 1.1 - Prob. 12ESCh. 1.1 - Prob. 13ESCh. 1.2 - Prob. 1ESCh. 1.2 - Prob. 2ESCh. 1.2 - Prob. 3ESCh. 1.2 - Prob. 4ESCh. 1.2 - Prob. 5ESCh. 1.2 - Prob. 6ESCh. 1.2 - Prob. 7ESCh. 1.2 - Prob. 8ESCh. 1.2 - Prob. 9ESCh. 1.2 - Prob. 10ESCh. 1.2 - Prob. 11ESCh. 1.2 - Prob. 12ESCh. 1.3 - Prob. 1ESCh. 1.3 - Prob. 2ESCh. 1.3 - Prob. 3ESCh. 1.3 - Prob. 4ESCh. 1.3 - Prob. 5ESCh. 1.3 - Prob. 6ESCh. 1.3 - Prob. 7ESCh. 1.3 - Prob. 8ESCh. 1.3 - Prob. 9ESCh. 1.3 - Prob. 10ESCh. 1.3 - Prob. 11ESCh. 1.3 - Prob. 12ESCh. 1.3 - Prob. 13ESCh. 1.3 - Prob. 14ESCh. 1.3 - Prob. 15ESCh. 1.3 - Prob. 16ESCh. 1.3 - Prob. 17ESCh. 1.3 - Prob. 18ESCh. 1.3 - Prob. 19ESCh. 1.3 - Prob. 20ES
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- In simplest way, For each quadratic relation, find the zeros and the maximum or minimum. a) y = x 2 + 16 x + 39 b) y = 5 x2 - 50 x - 120arrow_forwardIn simplest terms and step by step Write each quadratic relation in standard form, then fi nd the zeros. y = - 4( x + 6)2 + 36arrow_forwardIn simplest terms and step by step For each quadratic relation, find the zeros and the maximum or minimum. 1) y = - 2 x2 - 28 x + 64 2) y = 6 x2 + 36 x - 42arrow_forward
- Write each relation in standard form a)y = 5(x + 10)2 + 7 b)y = 9(x - 8)2 - 4arrow_forwardIn simplest form and step by step Write the quadratic relation in standard form, then fi nd the zeros. y = 3(x - 1)2 - 147arrow_forwardStep by step instructions The path of a soccer ball can be modelled by the relation h = - 0.1 d 2 + 0.5 d + 0.6, where h is the ball’s height and d is the horizontal distance from the kicker. a) Find the zeros of the relation.arrow_forward
- In simplest terms, Describe the shape and position of the parabola relative to the graph of y = x 2 y = - 80( x + 9) 2 + 10.8arrow_forwardas a Identify each equation Parabola, circle, ellipse perbola without completio the square. x²-6x-14 y = 33-y² 14y ofarrow_forwardI need the last answer t=? I did got the answer for the first two this is just homework.arrow_forward
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