Chapter 1.1, Problem 57E

a.

To determine

To find: the number of hits that player A have in 2011 regular season.

Answer to Problem 57E

  $132$

Explanation of Solution

Given:

Batting average of player A in 2011 = 0.296

Number of at-bats of player A in 2011 = 446

Let the number of hits of player A in 2011 be x .

Then,

  $\begin{array}{c}\text{Batting Average}=\frac{\text{Number of hits}}{\text{Number of at-bats}}\\ 0.296=\frac{x}{446}\\ 0.296\times 446=x\\ 132\approx x\end{array}$

Conclusion:

Player A had 132 hits in 2011 regular season.

b.

To determine

To explain: is it correct to say that the player B has more at-bats than the player A in 2011 season.

Answer to Problem 57E

No

Explanation of Solution

Given:

Player B has 33 fewer hits in 2011 season than player A but had a great batting average.

No, the statement is incorrect.

It is known that,

  $\text{Batting Average}=\frac{\text{Number of hits}}{\text{Number of at-bats}}$

Now since player B has 33 fewer hits in 2011 season than player A, so he must also had fewer at-bats so that it can have greater batting average.