Explanation Given: The given differential equation is x ( y ′ ) 2 − 4 y ′ − 12 x 3 = 0 . Calculation: Consider the given differential equation. x ( y ′ ) 2 − 4 y ′ − 12 x 3 = 0 Consider x as constant and use quadratic formula y ′ = − b ± b 2 − 4 a c 2 a to solve. y ′ = − ( − 4 ) ± ( − 4 ) 2 − 4 ( x ) ( − 12 x 3 ) 2 ( x ) = 4 ±

Differential Equations with Boundary-Value Problems (MindTap Course List)

9th Edition

ISBN: 9781305965799

Author: Dennis G. Zill

Publisher: Cengage Learning

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Differential Equations

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Chapter 1.1, Problem 56E

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Whether the equation x(y′)2−4y′−12x3=0 can be put into the normal form.

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Chapter 1.1, Problem 55E

Chapter 1.1, Problem 57E

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Differential Equations with Boundary-Value Problems (MindTap Course List)

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Whether the equation x ( y ′ ) 2 − 4 y ′ − 12 x 3 = 0 can be put into the normal form.

Solution Summary: The author explains that the differential equation x(yprime )2-4yere12x,3=0 can be put into the normal form.

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Whether the equation x(y′)2−4y′−12x3=0 can be put into the normal form.

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