Concept explainers
The human RefSeq of the entire first exon of a gene involved in Brugada syndrome (a cardiac disorder characterized by an abnormal electrocardiogram and an increased risk of sudden heart failure) is: 5′ CAACGCTTAGGATGTGCGGAGCCT 3′ The genomic DNA of four people (1–4), three of whom have the disorder, was subjected to single-molecule sequencing. The following sequences represent all those obtained from each person.
a. | The first exon of the RefSeq copy of this gene includes the start codon. Write as much of the amino acid sequence of the encoded protein as possible, indicating the N-to-C polarity. |
b. | Are any of these individuals homozygotes? If so, which person and what allele? |
c. | Is the inheritance of Brugada syndrome among these individuals dominant or recessive? |
d. | Is Brugada syndrome associated with allelic heterogeneity? |
e. | Are any of these individuals compound heterozygotes? |
f. | Do the data show any evidence for locus heterogeneity? |
g. | Which person has normal heart function? |
h. | For each variant from the RefSeq, describe: (i) what the mutation does to the coding sequence; and (ii) whether the variation is a loss-of-function allele, a gain-of-function allele, or a wild-type allele. |
i. | For each variant, indicate which of the following terms apply: null, hypomorphic, hypermorphic, nonsense, frameshift, missense, silent, SNP, DIP, SSR, anonymous. |
j. | Is the function of this gene haploinsufficient? Explain. |

a.
To determine:
The amino acid sequence for the RefSeq obtained from individual 1.
Introduction:
The mutation is the change in the nucleotide sequence of the gene, which results in either the formation of a defective protein or no protein at all. The mutation can also alter the regulation of certain genes leading to their hyperactivity or hypoactivity. It is different from recombination where gametes from parents are interchanged to produce new zygotes.
Explanation of Solution
The amino acid sequence for the RefSeq data 5' CAACGCTTAGGATGTGCGGAGCCT 3' will be N-glutamine-arginine-leucine-glycine-cysteine-alanine-glutamic acid-proline-C. The amino acid sequence for 5' CAACGCTTAGGATGTGCGGAGACT 3' is N-glutamine-arginine-leucine-glycine-cysteine-alanine-glutamic acid-threonine-C. The amino acid makes up large polypeptide chains that fold into functional proteins and perform different activities in the body of living organisms.

b.
To determine:
The presence of the homozygous individual.
Introduction:
The genes are the sequence of nucleotides that are present on the chromosomes and encode for a specific protein that plays a crucial role in the functioning of the different processes in an organism. The gene is located at specific gene loci and can be structural or regulatory in nature.
Explanation of Solution
The individual 2 is homozygous as the two strands of genetic material in the individual is same, and for all other individuals, the composition of nucleotides on both the strands is different. So, they are not homozygous for the given trait. The individual 2 has a nucleotide sequence 5' CAACGCTTAGGATGTGAGGAGCCT 3'. It implies that both the strands have similar nucleotide sequence. However, the homozygous allele cannot be predicted through the nucleotide sequence of the individual.

c.
To determine:
The inheritance pattern of Brugada syndrome among individuals.
Introduction:
The proteins are made of amino acids. The amino acids are of 20 types that combine in a varied manner to form proteins. The amino acids join together by peptide bonds. Proteins act as major substrates and reactants for the metabolic pathways. All the enzymes in the body that are crucial for the biochemical reactions are proteins.
Explanation of Solution
The inheritance of the disease, Brugada syndrome, is dominant as the disease develops by the inheritance of particular nucleotide sequence 5′ CAACGCTTAGGATGTGCGGAGCCT 3′ that is inherited by three organisms and has very little variation in the sequence structure due to mutation. The sequence is present in individual 1, 3, and 4, and accounts for the development of the disease when only one strand of the exon contains the sequence. So, implying that one copy is enough to cause the disease and therefore, the inheritance of the Brugada syndrome is dominant.

d.
To determine:
The association of Brugada syndrome with allelic heterogeneity.
Introduction:
The cardiovascular system is made of different components. The heart constitutes the primary organs of the system, and the arteries, veins, and blood capillaries form the associated structures of the cardiovascular system.
Explanation of Solution
Brugada syndrome is associated with allelic heterogeneity as the presence of only one copy of the sequence or allele in the exon can lead to the development of the disease. It implies that the disease can occur in heterozygous condition, where only one copy of allele is enough to cause disease. Hence, it can be concluded that Brugada syndrome is associated with allelic heterogeneity.

e.
To determine:
The presence of compound heterozygotes among individuals.
Introduction:
A genetic disorder is an alteration in the genetic composition of the individual for one or more genes that are manifested in the form of altered protein sequence for that particular trait. The genetic disorder is phenotypically manifested in various forms of abnormalities and malfunctions.
Explanation of Solution
Compound heterozygotes are the individuals who have two different mutations occurring in the two alleles of an individual. None of the individuals are compound heterozygotes, as only one of the copies of exon/allele is affected by mutation at a given time. The presence of only one mutation in one of the allele is a heterozygous condition. Hence, individuals 1, 3, and 4 are heterozygous, but not compound heterozygous.

f.
To determine:
The presence of locus heterogeneity among individuals.
Introduction:
The human consists of 23 pairs of chromosomes, condensed form of chromatids which divide during cell division into daughter cells. The human has 22 autosomes and one pair of sex chromosomes. The sex chromosomes determine the sex in an individual based on the type of sex chromosomes that are present in the fusing gametes.
Explanation of Solution
Locus heterogeneity is the condition where two different kinds of mutation occur at a different locus in the same chromosomes. None of the individuals has locus heterogeneity as all the individuals have only one mutation at one site or locus in the chromosome. Hence, none of the individuals shows locus heterogeneity.

g.
To determine:
The individual with normal heart function.
Introduction:
The chromosomes are condensed structures that are formed during the early phases of cell division from the loose network of chromatin thread and then regain their original structure after being divided into daughter cells.
Explanation of Solution
The individual who does not have the Brugada syndrome is individual 2, as the nucleotide sequence of the individual varies from the person who is positive for the cardiac disorder. The individual has changed single nucleotide in both the alleles and is therefore homozygous in nature. The difference in the nucleotide sequence in both the alleles accounts for normal heart function in individual 2.

h.
To determine:
The effect of the mutation on the coding sequence.
Introduction:
Fertilization is the process by which the male gamete, sperm, fertilize with the female gamete, ovary. The process brings about the fusion of two haploid pronuclei into a diploid zygote.
Explanation of Solution
The changes occurred due to a mutation in coding sequence are that in individual 1 there is a change in amino acid sequence as the amino acid proline is changed to threonine. In individual 2, the change in amino acid sequence occurs from alanine to glutamine. In individual 3, there is a change of amino acid sequence cysteine to alanine, and in individual 4, the amino acid changes from alanine to valine. The effect of this mutation as loss-of-function or gain-of-function can be done by protein expression analysis. The three individuals are not wild type due to the presence of the mutation.

i.
To determine:
The type of mutation in the sequence.
Introduction:
There are a vast number of cardiovascular problems that can arise due to malformation in the heart or the dysfunction of some parts of the cardiovascular system. Some of these disorders are fibrillation, septal defects, and so on.
Explanation of Solution
The mutation in all the individuals is single nucleotide polymorphisms (SNPs) as there is a change only in one nucleotide and not the entire codon. The presence of silent, missense, or nonsense mutation can only be done with the help of protein expression analysis through techniques like microarray and so on.

j.
To determine:
The presence of gene haploinsufficiency in the function.
Introduction:
The circulatory system and cardiovascular systems form the two very important different organ systems in the body. The system is responsible for pumping the blood carrying nutrients and oxygen and helping to remove waste products from the body.
Explanation of Solution
Gene haploinsufficiency is the condition in which normal phenotype needs the protein to encode by both the alleles, and there is a reduction in the function by 50% if any one of the alleles has the abnormal phenotype. The presence of a mutation in the genome of all the individual increases the probability of gene haploinsufficiency. The change in the phenotype of the alleles of the exon due to mutation can account for gene haploinsufficiency in the individuals.
Want to see more full solutions like this?
Chapter 11 Solutions
ND STONY BROOK UNIVERSITY LOOSELEAF GENETICS: FROM GENES TO GENOMES
- Ch.23 How is Salmonella able to cross from the intestines into the blood? A. it is so small that it can squeeze between intestinal cells B. it secretes a toxin that induces its uptake into intestinal epithelial cells C. it secretes enzymes that create perforations in the intestine D. it can get into the blood only if the bacteria are deposited directly there, that is, through a puncture — Which virus is associated with liver cancer? A. hepatitis A B. hepatitis B C. hepatitis C D. both hepatitis B and C — explain your answer thoroughlyarrow_forwardCh.21 What causes patients infected with the yellow fever virus to turn yellow (jaundice)? A. low blood pressure and anemia B. excess leukocytes C. alteration of skin pigments D. liver damage in final stage of disease — What is the advantage for malarial parasites to grow and replicate in red blood cells? A. able to spread quickly B. able to avoid immune detection C. low oxygen environment for growth D. cooler area of the body for growth — Which microbe does not live part of its lifecycle outside humans? A. Toxoplasma gondii B. Cytomegalovirus C. Francisella tularensis D. Plasmodium falciparum — explain your answer thoroughlyarrow_forwardCh.22 Streptococcus pneumoniae has a capsule to protect it from killing by alveolar macrophages, which kill bacteria by… A. cytokines B. antibodies C. complement D. phagocytosis — What fact about the influenza virus allows the dramatic antigenic shift that generates novel strains? A. very large size B. enveloped C. segmented genome D. over 100 genes — explain your answer thoroughlyarrow_forward
- What is this?arrow_forwardMolecular Biology A-C components of the question are corresponding to attached image labeled 1. D component of the question is corresponding to attached image labeled 2. For a eukaryotic mRNA, the sequences is as follows where AUGrepresents the start codon, the yellow is the Kozak sequence and (XXX) just represents any codonfor an amino acid (no stop codons here). G-cap and polyA tail are not shown A. How long is the peptide produced?B. What is the function (a sentence) of the UAA highlighted in blue?C. If the sequence highlighted in blue were changed from UAA to UAG, how would that affecttranslation? D. (1) The sequence highlighted in yellow above is moved to a new position indicated below. Howwould that affect translation? (2) How long would be the protein produced from this new mRNA? Thank youarrow_forwardMolecular Biology Question Explain why the cell doesn’t need 61 tRNAs (one for each codon). Please help. Thank youarrow_forward
- Molecular Biology You discover a disease causing mutation (indicated by the arrow) that alters splicing of its mRNA. This mutation (a base substitution in the splicing sequence) eliminates a 3’ splice site resulting in the inclusion of the second intron (I2) in the final mRNA. We are going to pretend that this intron is short having only 15 nucleotides (most introns are much longer so this is just to make things simple) with the following sequence shown below in bold. The ( ) indicate the reading frames in the exons; the included intron 2 sequences are in bold. A. Would you expected this change to be harmful? ExplainB. If you were to do gene therapy to fix this problem, briefly explain what type of gene therapy youwould use to correct this. Please help. Thank youarrow_forwardMolecular Biology Question Please help. Thank you Explain what is meant by the term “defective virus.” Explain how a defective virus is able to replicate.arrow_forwardMolecular Biology Explain why changing the codon GGG to GGA should not be harmful. Please help . Thank youarrow_forward
- Stage Percent Time in Hours Interphase .60 14.4 Prophase .20 4.8 Metaphase .10 2.4 Anaphase .06 1.44 Telophase .03 .72 Cytukinesis .01 .24 Can you summarize the results in the chart and explain which phases are faster and why the slower ones are slow?arrow_forwardCan you circle a cell in the different stages of mitosis? 1.prophase 2.metaphase 3.anaphase 4.telophase 5.cytokinesisarrow_forwardWhich microbe does not live part of its lifecycle outside humans? A. Toxoplasma gondii B. Cytomegalovirus C. Francisella tularensis D. Plasmodium falciparum explain your answer thoroughly.arrow_forward
- Biology: The Dynamic Science (MindTap Course List)BiologyISBN:9781305389892Author:Peter J. Russell, Paul E. Hertz, Beverly McMillanPublisher:Cengage LearningBiology 2eBiologyISBN:9781947172517Author:Matthew Douglas, Jung Choi, Mary Ann ClarkPublisher:OpenStaxHuman Heredity: Principles and Issues (MindTap Co...BiologyISBN:9781305251052Author:Michael CummingsPublisher:Cengage Learning
- Case Studies In Health Information ManagementBiologyISBN:9781337676908Author:SCHNERINGPublisher:CengageConcepts of BiologyBiologyISBN:9781938168116Author:Samantha Fowler, Rebecca Roush, James WisePublisher:OpenStax College




