
(a):
Calculate the annual worth.
(a):

Explanation of Solution
Defender: Upgrade cost (UC) is $79,000. Market value (MV) is $40,000. Annual operating cost (AC) is $85,000. Salvage value (SV) is $30,000. Interest rate (i) is 15%. Time period (n) is 3.
Challenger: First cost (FC) is $220,000. Annual operating cost (AC) is $45,000. Salvage value (SV) is $50,000. . Interest rate (i) is 15%. Time period (n) is 3.
Annual worth (AV) of defender can be calculated as follows:
The annual worth of the defender is -$128,479.33.
Annual worth (AV) of challenger can be calculated as follows:
The annual worth of the challenger is -$126,954.9.
The challenger can be replaced, if the annual cost of challenger is lower than the defender. Thus, the firm can replace the defender for the challenger.
(b):
Calculate the annual worth for the next three years.
(b):

Explanation of Solution
The annual worth for the next three years is -$126,954.9, which is calculated in the subpart ‘a’.
(c):
Calculate the annual worth through spreadsheet.
(c):

Explanation of Solution
The spreadsheet function to calculate the annual worth of defender through the spreadsheet is given below:
= -PMT(15%,3,-119000,30000)-85000
The above function gives the value of -$128,479.95.
The spreadsheet function to calculate the annual worth of challenger through the spreadsheet is given below:
= -PMT(15%,3,-220000,50000)-45000
The above function gives the value of -$126,956.08.
(d):
Calculate the annual worth through spreadsheet for 8 years.
(d):

Explanation of Solution
The spreadsheet function to calculate the annual worth of challenger for 8 years through the spreadsheet is given below:
= -PMT(15%,8,-220000,10000)-45000
The above function gives the value of -$93,298.52. This reveals that there is a reduction of $33,657.56 per year recovery from the annual worth of the challenger with the 3 year time period.
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Chapter 11 Solutions
ENGINEERING ECONOMY(LOOSELEAF)
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