Chapter 11, Problem 31E

Interpretation Introduction

Interpretation:

The pressure in $\text{Pa}$ is to be converted in $\text{atm}$, $\text{mmHg}$, $\text{torr}$ and $\text{psi}$.

Concept Introduction:

The simplest unit to measure pressure is atmospheres $\left(\text{atm}\right)$.

Pascal $\left(\text{Pa}\right)$ is the SI unit of pressure.

The third unit to measure pressure is millimetres of mercury $\left(\text{mm Hg}\right)$.

The relation between $\text{Pa}$ and $\text{atm}$ is:

$1\text{ Pa}=0.000009869\text{ atm}$

The relation between $\text{Pa}$ to $\text{mm Hg}$ is:

$1\text{ Pa}=0.0075\text{ mm Hg}$

The relation between $\text{Pa}$ to $\text{torr}$ is:

$1\text{ Pa}=0.0075\text{ torr}$

The relation between $\text{mmHg}$ and $\text{psi}$ is:

$1\text{ Pa}=0.000145\text{ psi}$