EBK STUDENT SOLUTIONS MANUAL WITH STUDY
EBK STUDENT SOLUTIONS MANUAL WITH STUDY
10th Edition
ISBN: 9781337520386
Author: Vuille
Publisher: YUZU
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Question
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Chapter 11, Problem 30P

(a)

To determine

Five thermal energy transfers that occur.

(a)

Expert Solution
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Explanation of Solution

Aluminum container at 20°C contains ethyl alcohol at 30°C and ice at 0°C . Heat transfer from hot to cold body occurs. The mixture and the container attains an equilibrium temperature.

Ice at 10°C increases in temperature and becomes Ice at 0°C , then phase change occurs from ice to cold water at 0°C , then the temperature of the cold water at 0°C raises to a value T. Temperature of the Aluminum container at 20°C raises to a value T and ethyl alcohol at 30°C temperature rises to a value. The mixture and the container attain an equilibrium temperature T.

Conclusion: All the five thermal energy transfer that occurs is identified.

(b)

To determine

Construct a table similar to table 11.5

(b)

Expert Solution
Check Mark

Explanation of Solution

A comprehensive table is constructed for all the five thermal energy transfers.

Q m(kg) c(J/kg°C) L(J/kg) Tf(°C) Ti(°C) Expressions
Qice 1.00 2090 - 0 10.0 micecice[TfTi]=micecice[0(10.0°C)]
Qmelt 1.00 - 3.33×105 0 0 miceLf
Qwater 1.00 4186 - T 0 micecwater[TfTi]=micecwater[Tf0]
QAl 0.500 900 - T 20.0 mAlcAl[TfTi]=mAlcAl[Tf20.0°C]
QEAlc 6.00 2430 - T 30.0 mEAlccEAlc[TfTi]=mEAlccEAlc[Tf30.0°C]

Conclusion:

The comprehensive table similar to table 11.5 is constructed.

(c)

To determine

Conservation of energy equation.

(c)

Expert Solution
Check Mark

Explanation of Solution

According to the conservation of energy, heat lost by one in a mixture is equal to heat gained by the other.

Summing up all the energy expressions and equating it to zero.

{micecice[0(10.0°C)]+miceLf+micecwater[Tf0]+mAlcAl[Tf20.0°C]+mEAlccEAlc[Tf30.0°C]=0}

Conclusion:

The equation denoting the conservation of energy after summing up all the expression and setting it to zero is constructed.

(d)

To determine

The final equilibrium temperature.

(d)

Expert Solution
Check Mark

Answer to Problem 30P

The final equilibrium temperature is T=4.81°C

Explanation of Solution

Given Info: Mass of aluminum container is 0.500 kg, initial temperature of the aluminum container is 20.0°C , mass of ethyl alcohol is 6.00 kg, initial temperature of ethyl alcohol is 30.0°C , mass of ice is 100 kg, initial temperature of ice is 10.0°C .

Formula to calculate the heat gained by cold water is,

{micecice[0(10.0°C)]+miceLf+micecwater[Tf0]+mAlcAl[Tf20.0°C]+mEAlccEAlc[Tf30.0°C]=0}

Rearrange in terms of Tf .

{micecice(10.0°C)+miceLf+micecwaterTf+mAlcAlTfmAlcAl(20.0°C)+mEAlccEAlcTfmEAlccEAlc(30.0°C)}=0micecwaterTf+mAlcAlTf+mEAlccEAlcTf={micecice(10.0°C)miceLf+mAlcAl(20.0°C)+mEAlccEAlc(30.0°C)}Tf={mice[cice(10.0°C)+Lf]+mAlcAl(20.0°C)+mEAlccEAlc(30.0°C)}micecwater+mAlcAl+mEAlccEAlc

Substitute all quantities in the second through sixth columns into the last column and sum to find T.

Tf={(1.00kg)[(2090J/kg°C)(10.0°C)+(3.33×105J/kg)]+[(0.500kg)(900J/kg°C)(20.0°C)]+[(6.00kg)(2430J/kg°C)(30.0°C)]}((1.00kg)(4186J/kg°C)+(0.500kg)(900J/kg°C)+[(6.0kg)(2430J/kg°C)])=9250019216=4.81°C

Conclusion:

Therefore, the final equilibrium temperature is 4.81°C .

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Chapter 11 Solutions

EBK STUDENT SOLUTIONS MANUAL WITH STUDY

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